Alphabeta Math
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Projected CUR has a two-sided Frobenius residual bound

Statement

Let F∈{R,C}, m,n≥1, A∈Fm×n, and choose an integer 0≤k≤min⁡(m,n) and ordered lists I,J of k distinct valid row and column indices, respectively. Set C=A(:,J) and R=A(I,:) as in Skeleton and projected least-squares CUR cores, and define PC=CC† and PR=R†R. The projected least-squares CUR approximation is A^proj=C(C†AR†)R=PCAPR. With ∥X∥F=(∑i,j∣Xij∣2)1/2,

∥A−A^proj∥F≤∥(Im−PC)A∥F+∥A(In−PR)∥F.

This bound is for the projected least-squares core only; it is not asserted for the skeleton core W†.

Facts & Assumptions

Given: A finite real or complex matrix A, selected matrices C,R, and their unique Moore-Penrose inverses.

[F1]

Skeleton and projected least-squares CUR cores: the projected core is C†AR† and its reconstruction is (CC†)A(R†R).

[F2]

The Moore-Penrose products are orthogonal projectors: CC† and R†R are orthogonal projections.

Proof

1.1F1F2given

Put PC=CC† and PR=R†R. By [F1], A^proj=PCAPR, and [F2] makes both factors orthogonal projections.

2.1step 1.1algebra

Algebra gives A−PCAPR=(Im−PC)A+PCA(In−PR).

3.1step 1.1step 2.1algebra∎

For an orthogonal projection P and each column vector x, the decomposition x=Px+(I−P)x is orthogonal, so ∥Px∥2≤∥x∥2. Summing squared column norms gives ∥PY∥F≤∥Y∥F for every compatible matrix Y. The Frobenius norm is the Euclidean norm of the entries, so its triangle inequality applied to step 2.1 and this contraction with P=PC, Y=A(In−PR) gives the asserted bound.

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