Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-adaptedprecheck passaudited 2026-08-28
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Decreasing limits of plurisubharmonic functions

Statement

Let Ω⊆Cm be a domain and let u1≥u2≥⋯ be a decreasing sequence of plurisubharmonic functions on Ω. Put u(z)=lim⁡n→∞un(z). Then either u≡−∞ on a connected component of Ω, or u is plurisubharmonic on Ω.

Facts & Assumptions

Given: A decreasing sequence (un) of plurisubharmonic functions on a domain Ω⊆Cm.

[L1]

Plurisubharmonicity is the affine-line subharmonicity test together with upper semicontinuity and the componentwise nontriviality condition (Plurisubharmonic functions).

[L2]

A decreasing limit of subharmonic functions is subharmonic or identically −∞ on the connected component (A decreasing limit of plane subharmonic functions is subharmonic or identically -infinity).

Proof

technique · direct
1.1given

A decreasing limit of upper semicontinuous functions is upper semicontinuous, so u is upper semicontinuous on Ω. If u≡−∞ on some connected component, the first alternative of the statement holds and there is nothing further to prove.

2.1L1L2step 1.1∎

Fix a∈Ω and v≠0. On every connected component of the line domain {λ:a+λv∈Ω}, each restriction λ↦un(a+λv) is subharmonic or identically −∞ by [L1]. Therefore [L2] makes the limit restriction λ↦u(a+λv) subharmonic or identically −∞ there. Since the componentwise −∞ alternative was excluded in step 1.1, [L1] now shows that u is plurisubharmonic on Ω.

Depends on

Used by

Dependency tree · two levels

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Sources