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A Dedekind domain is a PID exactly when its class group is trivial
Statement
Assume the Axiom of Choice.
Let be a Dedekind domain. Then is a principal ideal domain if and only if its ideal class group is trivial.
Facts & Assumptions
Given: The Axiom of Choice and a Dedekind domain .
A principal ideal domain is a domain in which every ideal is principal (Principal ideal domain).
The class group is the quotient of nonzero fractional ideals by principal fractional ideals (The ideal class group).
Nonzero ideals factor uniquely into prime powers in a Dedekind domain (Unique factorization of nonzero fractional ideals into prime powers).
Multiplication descends to the class-group quotient (The ideal class group quotient is well defined).
Proof
If is a PID, then every nonzero fractional ideal is principal, so the quotient in [F2] has exactly one class. Thus is trivial.
Conversely, assume is trivial. Then every nonzero prime ideal has trivial class and is therefore principal. By [L1], every nonzero integral ideal is a finite product of principal prime ideals, hence principal. Therefore [F1] makes a PID.
This proves the equivalence.
Depends on
Used by
Dependency tree · two levels
11 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- J. S. Milne, A Primer of Commutative Algebra, §20 (standard reference, not scraped)
- Mircea Mustata, Introduction to Commutative Algebra, §8.5 (standard reference, not scraped)