Alphabeta Math
TheoremStatement: Literature-sourcedProof: Literature-sourcedprecheck passjudge pass (gpt-5.6-terra)audited 2026-08-31
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

A Dedekind domain is a PID exactly when its class group is trivial

Statement

Assume the Axiom of Choice.

Let R be a Dedekind domain. Then R is a principal ideal domain if and only if its ideal class group Cl(R) is trivial.

Facts & Assumptions

Given: The Axiom of Choice and a Dedekind domain R.

[F1]

A principal ideal domain is a domain in which every ideal is principal (Principal ideal domain).

[F2]

The class group is the quotient of nonzero fractional ideals by principal fractional ideals (The ideal class group).

[L1]

Nonzero ideals factor uniquely into prime powers in a Dedekind domain (Unique factorization of nonzero fractional ideals into prime powers).

[L2]

Multiplication descends to the class-group quotient (The ideal class group quotient is well defined).

Proof

technique · direct
1.1

If R is a PID, then every nonzero fractional ideal is principal, so the quotient in [F2] has exactly one class. Thus Cl(R) is trivial.

F1F2given
1.2

Conversely, assume Cl(R) is trivial. Then every nonzero prime ideal has trivial class and is therefore principal. By [L1], every nonzero integral ideal is a finite product of principal prime ideals, hence principal. Therefore [F1] makes R a PID.

F1F2L1L2given
2.1

This proves the equivalence.

step 1.1step 1.2

Depends on

Used by

Dependency tree · two levels

11 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources