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TheoremStatement: AI-adaptedProof: AI-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-08-31
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The derivative of the simple spectral projector is expressed by the reduced resolvent and the perturbation

Statement

Let A(t) be differentiable, let λ(t) be a simple eigenvalue branch, let P(t) be the corresponding simple spectral projector, and let S be the reduced resolvent at t=0. Then

P(0)=SA(0)P(0)P(0)A(0)S.

Facts & Assumptions

Given: A differentiable simple spectral projector branch P(t) for a simple eigenvalue branch of A(t), and the reduced resolvent S at t=0.

[L1]

The reduced resolvent satisfies SP=PS=0 and S(AλI)=(AλI)S=IP (The reduced resolvent satisfies the standard projector and inverse identities on the complementary invariant subspace).

Proof

technique · direct
1.1

Differentiate (AλI)P=0 at t=0: (A(0)λ(0)I)P+(AλI)P=0. Left-multiplying by S and using [L1] together with SP=0 gives (IP)P=SA(0)P. Differentiating P(AλI)=0 and right-multiplying by S similarly gives P(IP)=PA(0)S.

L1givenalgebra
2.1

Differentiating P2=P gives P=PP+PP. Because PPP=0, this decomposes as P=(IP)PP+PP(IP). Substituting the two identities from step 1.1 yields P=SA(0)PPA(0)S, which is the claimed formula.

L1step 1.1algebra

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Dependency tree · two levels

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