Alphabeta Math
TheoremStatement: AI-adaptedProof: AI-generatedprecheck passaudited 2026-08-31
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

In a fixed gauge, the derivative of a simple right eigenvector is obtained by applying the reduced resolvent to the perturbation

Statement

Let A(t) be differentiable, let λ(t) be a simple eigenvalue branch, and let x(t) be the right eigenvector branch chosen in the fixed gauge y0∗x(t)=1, where y0 is the left eigenvector at t=0. If S is the reduced resolvent at t=0, then

x′(0)=−SA′(0)x(0).

Facts & Assumptions

Given: A differentiable simple eigenpair branch in the fixed gauge y0∗x(t)=1 and the reduced resolvent S at t=0.

[L1]

The reduced resolvent satisfies S(A−λI)=I−P and Sx=0 (The reduced resolvent satisfies the standard projector and inverse identities on the complementary invariant subspace).

[L2]

Proof

technique · direct
1.1L1L2givenalgebra

Differentiate (A−λI)x=0 at t=0: (A′(0)−λ′(0)I)x+(A−λI)x′=0. Apply S and use [L1]: x′−Px′=−S(A′(0)−λ′(0)I)x. Because the fixed gauge gives y0∗x′(0)=0, the derivative x′(0) lies in ker⁡y0∗, so Px′(0)=x(y0∗x′(0))=0.

2.1L1step 1.1algebra∎

Step 1.1 therefore gives x′(0)=−S(A′(0)−λ′(0)I)x(0). Since Sx(0)=0 by [L1], the λ′(0) term disappears and x′(0)=−SA′(0)x(0).

Depends on

Used by

Dependency tree · two levels

8 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources