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In a fixed gauge, the derivative of a simple right eigenvector is obtained by applying the reduced resolvent to the perturbation
Statement
Let be differentiable, let be a simple eigenvalue branch, and let be the right eigenvector branch chosen in the fixed gauge , where is the left eigenvector at . If is the reduced resolvent at , then
Facts & Assumptions
Given: A differentiable simple eigenpair branch in the fixed gauge and the reduced resolvent at .
The reduced resolvent satisfies and (The reduced resolvent satisfies the standard projector and inverse identities on the complementary invariant subspace).
The eigenvalue derivative is (Along a differentiable matrix path, a simple eigenvalue satisfies under the normalization ).
Proof
Differentiate at : Apply and use [L1]: Because the fixed gauge gives , the derivative lies in , so .
Step 1.1 therefore gives . Since by [L1], the term disappears and .
Depends on
- The reduced resolvent satisfies the standard projector and inverse identities on the complementary invariant subspace
- Along a differentiable matrix path, a simple eigenvalue satisfies $\lambda'=y^*A'x$ under the normalization $y^*x=1$
- A simple eigenvalue and a gauge-fixed right eigenvector admit local $C^1$ branches in the underlying real matrix space
Used by
Dependency tree · two levels
8 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- G. W. Stewart and Ji-guang Sun, Matrix Perturbation Theory (standard reference, not scraped)