How statement and proof provenance work
The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.
- Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
- AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
- AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.
These labels describe origin, not correctness: citations and verification chips remain separate evidence.
Minimal van Kampen area agrees with minimal algebraic relator area
Statement
For a null word in a finite presentation, the minimal area of a van Kampen diagram equals its minimal algebraic relator area.
Facts & Assumptions
Given: A finite presentation and a word representing the identity.
Van Kampen diagrams exist exactly for null words in the presented group (A word is trivial in a presented group exactly when it bounds a finite van Kampen diagram).
Algebraic relator area is the minimum number of conjugates of defining relators needed to express the word, when such a minimum exists (Algebraic relator area and the Dehn function of a finite presentation, Every null word has a minimal algebraic relator area).
Proof
Let be any van Kampen diagram for with faces. Reading the faces one by one as in the proof of The boundary label of a van Kampen diagram is trivial in the presented group expresses as a product of conjugates of relators and their inverses. Hence the algebraic relator area of is at most .
Conversely, let be an algebraic expression with minimal as in [F1]. The converse construction in A word is trivial in a presented group exactly when it bounds a finite van Kampen diagram produces a van Kampen diagram with exactly faces and boundary word . Therefore the minimal diagram area is at most the algebraic relator area.
Step 1.1 gives one inequality between the two minima and step 1.2 gives the reverse inequality. Therefore the two minimal areas are equal.
Depends on
Used by
Dependency tree · two levels
6 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- GAP SmallCancellation manual, Chapter 1: Small Cancellation Theory — the classical conditions (standard reference, not scraped)
- Jay Williams, Universal Countable Borel Quasi-Orders (standard reference, not scraped)
- Nicholas Touikan, An Introduction to Combinatorial and Geometric Group Theory, Section 3.5 (standard reference, not scraped)
- Clara Löh, Geometric Group Theory: An Introduction, Section 7.4.1 (standard reference, not scraped)