Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-generatedprecheck passaudited 2026-09-01
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

A word is trivial in a presented group exactly when it bounds a finite van Kampen diagram

Statement

Let G=XR and let w be a word on X±1. Then w represents the identity in G if and only if w is the boundary label of a finite van Kampen diagram over XR.

Facts & Assumptions

Given: A presentation G=XR and a word w on X±1.

[L1]

The boundary label of every van Kampen diagram is trivial in the presented group (The boundary label of a van Kampen diagram is trivial in the presented group).

[F1]

A word lies in the normal closure of R exactly when it is a finite product of conjugates of relators and their inverses (The normal closure of R is the set of finite products of conjugates of elements of R and their inverses).

Proof

technique · direct
1.1

If w is the boundary label of a finite van Kampen diagram, then [L1] says that w represents the identity in G.

L1given
1.2

Conversely, suppose that w represents the identity in G. Then w lies in the normal closure of R, so [F1] gives a factorisation w=k=1mukrkεkuk1 with rkR and εk{±1}.

F1given
2.1

For each factor ukrkεkuk1, take one 2-cell with boundary word rkεk and attach to its boundary a whisker labelled uk from a common basepoint. Gluing these m discs along the whiskers produces a finite planar diagram whose outer boundary label is exactly the product in step 1.2, namely w.

step 1.2construct
3.1

Steps 1.1 and 2.1 prove both directions of the equivalence.

step 1.1step 2.1

Depends on

Used by

Dependency tree · two levels

9 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources