Alphabeta Math
TheoremStatement: Literature-sourcedProof: Literature-sourcedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-06
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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Poisson summation

Statement

For every Schwartz function f under f^(ξ)=∫f(x)e(−xξ)dx, ∑n∈Zf(n)=∑m∈Zf^(m).

Facts & Assumptions

Given: A Schwartz function f.

Proof

technique · direct
1.1given

Define the periodization F(x)=∑n∈Zf(x+n). Schwartz decay makes this series, and every termwise derivative series, converge uniformly on compact sets, so F is a smooth 1-periodic function.

2.1step 1.1

Its mth Fourier coefficient is ∫01F(x)e(−mx) dx=∑n∈Z∫01f(x+n)e(−m(x+n)) dx=f^(m), where absolute convergence justifies interchange and the intervals [n,n+1] partition R.

3.1step 2.1∎

The sequence (f^(m))m∈Z is rapidly decreasing, so the Fourier series of F converges absolutely and uniformly to F. Evaluating at 0 gives ∑n∈Zf(n)=F(0)=∑m∈Zf^(m).

Used by

Dependency tree · 0 levels

Nothing. This result depends on no other item in the library.

Sources