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TheoremStatement: Literature-sourcedProof: AI-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-08-31
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Dirichlet's hyperbola method for summatory convolutions

Statement

Let f,g be arithmetic functions with summatory functions F(y)=∑n≤yf(n) and G(y)=∑n≤yg(n) (Summatory functions and average orders). If x≥1 and U,V≥1 satisfy UV=x, then

∑n≤x(f∗g)(n)=∑a≤Uf(a)G(x/a)+∑b≤Vg(b)F(x/b)−F(U)G(V).

Facts & Assumptions

Given: Arithmetic functions f,g, a real x≥1, and reals U,V≥1 with UV=x.

Proof

technique · direct
1.1givenalgebra

By Dirichlet convolution of arithmetic functions, ∑n≤x(f∗g)(n)=∑n≤x∑d∣nf(d)g(n/d)=∑ab≤xf(a)g(b), where the last equality is the finite reindexing of Finite commutative-monoid sums are invariant under bijective reindexing, split over disjoint unions, and satisfy the finite Fubini rule.

2.1step 1.1givenalgebra

Every lattice point (a,b) with ab≤x=UV lies in at least one of the regions a≤U or b≤V, for otherwise a>U and b>V would give ab>UV=x. Therefore ∑ab≤xf(a)g(b)=∑ab≤xa≤Uf(a)g(b)+∑ab≤xb≤Vf(a)g(b)−∑a≤Ub≤Vf(a)g(b).

3.1step 2.1givenalgebra∎

For fixed a≤U, the inner sum over b is exactly G(x/a), and for fixed b≤V the inner sum over a is exactly F(x/b). The overlap sum factors as (∑a≤Uf(a))(∑b≤Vg(b))=F(U)G(V). Substituting these identities into step 2.1 gives the claimed formula.

Depends on

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Sources