Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedprecheck passjudge pass (gpt-6.1-sol)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Domain of dependence and local uniqueness

Statement

Assume the Axiom of Countable Choice (The Axiom of Countable Choice (ACω)). Let n≥1, c>0, x0∈Rn, t0>0, and let u,v∈C2 solve □cu=f and □cv=g on a neighbourhood of the closed backward cone K−(x0,t0) (Forward and backward wave cones, domain of dependence and influence). If f=g on K−(x0,t0) and u(⋅,0)=v(⋅,0), ut(⋅,0)=vt(⋅,0) on the base ball Bct0(x0), then u=v on K−(x0,t0).

This is the formal content, required by the design's well-definedness note, of the phrase "the value at (x0,t0) depends only on the Cauchy data on the base ball and the source on the cone".

Facts & Assumptions

Given: ACω; two C2 functions u,v solving □cu=f, □cv=g near the cone K−(x0,t0), with f=g on the cone and equal Cauchy data on the base ball Bct0(x0).

[F1]

Finite propagation: if w solves □cw=h near K−(x′,t′) with h=0 on the cone and zero Cauchy data on its base ball, then w=0 on K−(x′,t′). (Finite propagation speed for the wave equation)

Proof

1.1givenF2

The difference solves a homogeneous equation on the cone: w:=u−v is C2 on a neighbourhood of K−(x0,t0) and, by linearity of differentiation [F2], □cw=f−g, which vanishes on the cone because f=g there; moreover w(⋅,0)=0 and wt(⋅,0)=0 on the base ball Bct0(x0) because the Cauchy data of u and v agree there.

2.1step 1.1F1∎

Conclusion: the hypotheses of [F1] are met by w on the cone K−(x0,t0), so w=0 there, that is, u=v on K−(x0,t0); in particular the value at the vertex is determined by the base data and the source on the cone.

Depends on

Used by

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Sources