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Hartogs pseudoconvexity yields a continuous plurisubharmonic exhaustion
Statement
Let be a domain. If is Hartogs pseudoconvex, that is, if is plurisubharmonic on , then admits a continuous plurisubharmonic exhaustion function.
Facts & Assumptions
Given: A domain .
Hartogs pseudoconvexity means exactly that is plurisubharmonic, while a continuous plurisubharmonic exhaustion is defined by compact sublevel sets (Plurisubharmonic exhaustions and Hartogs pseudoconvexity).
Finite maxima preserve plurisubharmonicity (Basic stability operations for plurisubharmonic functions).
The squared norm has positive Levi form, so it is plurisubharmonic (The Levi form and strict plurisubharmonicity, The C^2 Levi criterion for plurisubharmonicity).
Proof
Assume that is plurisubharmonic. The function is plurisubharmonic by [L3]. Since is a distance-to-the-complement function for the sup norm, it is continuous on , so is continuous as well. Therefore [L2] makes a continuous plurisubharmonic function.
As approaches , the term tends to , and as inside , the term tends to . Hence the sublevel sets of are compact in , so is a continuous plurisubharmonic exhaustion.
Depends on
Used by
Dependency tree · two levels
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Sources
- Jiří Lebl, Tasty Bits of Several Complex Variables, Theorem 2.5.6 (standard reference, not scraped)
- Harold P. Boas, Lecture Notes on Several Complex Variables, Theorem 8 (standard reference, not scraped)