Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-generatedPipeline-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-09-06
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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
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Existence of Schur covering groups

Statement

Every finite group has a Schur covering group.

Facts & Assumptions

Given: Let G=F/R be a finite presentation and put A=R/[F,R] and M=(R[F,F])/[F,R].

Proof

technique · direct
1.1

The quotient A/MR/(R[F,F]) embeds in the free abelian group Fab, so it is free abelian. Hence 0MAA/M0 splits. Choose a complement S/[F,R] to M in A.

givenalgebra
2.1

The extension R/SF/SG is central because [F,R]S. Its kernel is R/SM(G) by Hopf's formula, and it lies in [F/S,F/S] because the chosen complement meets M trivially. Thus it is a stem extension with multiplier kernel. The kernel and G are finite, so F/S is finite, and Schur covering group makes it a Schur cover.

step 1.1algebra

Depends on

Used by

Dependency tree · two levels

11 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources