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TheoremStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedaudited 2026-09-22
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Existence theorem for complex semisimple Lie algebras

Statement

Assume the Axiom of Choice. For every reduced crystallographic root system Φ there are a finite-dimensional complex semisimple Lie algebra g, a Cartan subalgebra of g, and an isomorphism from Φ onto the resulting root system. If Φ is nonempty and irreducible, g may be taken simple. For the empty root system, g may be taken to be the zero Lie algebra.

Facts & Assumptions

Given: A reduced crystallographic root system Φ.

[A1]

AC is assumed and is used through the Serre presentation theorem (The Axiom of Choice).

[L1]

The irreducible components Φj are reduced crystallographic root systems with pairwise orthogonal spans whose sum is the ambient space; the decomposition is unique (Unique irreducible decomposition).

[L2]

A regular vector determines a positive system and its simple roots; those simple roots form a basis, and every root has integral coordinates of one sign in that basis (Positive systems and simple roots, Simple roots form a signed integral basis).

[L3]

For a finite-type Cartan matrix A the Serre algebra g(A) is finite-dimensional and semisimple, with Cartan matrix A and root system Φ(A). If A is the Cartan matrix of an irreducible component of a reduced crystallographic root system, then g(A) is simple (Serre presentation theorem).

[L4]

Two based reduced crystallographic root systems with the same Cartan matrix are isomorphic by the linear map that matches their ordered bases (The Cartan matrix determines a based root system).

[L5]

The zero Lie algebra is semisimple but not simple (Simple, semisimple, and reductive Lie algebras).

Proof

technique · direct
1.1

If Φ=, then its ambient space is zero because Φ spans it. Taking g=0 gives the empty root system and a semisimple algebra by [L5], proving the empty case. Henceforth suppose Φ.

L5algebra
1.2

Choose a regular vector and the resulting base Δ by [L2]. By [L1], write Φ=Φ1Φm. The restriction of the regular vector to Ej=spanΦj is regular for Φj, and positivity is tested componentwise, so Δ is the disjoint union of the bases Δj=ΔΦj. Let Aj be the Cartan matrix of (Φj,Δj); the Cartan matrix of Φ is the block diagonal matrix diag(A1,,Am).

L1L2algebra
1.3

For each j, [L3] gives a finite-dimensional semisimple Serre algebra g(Aj) with based root system Ψj having Cartan matrix Aj. By [L4], the base-matching map is a root-system isomorphism φj:ΦjΨj. Since Aj is the Cartan matrix of the irreducible component Φj, [L3] also makes g(Aj) simple.

L1L3L4algebra
2.1

Put g=j=1mg(Aj) and take the direct sum of the Cartan subalgebras supplied by [L3]. Brackets between distinct summands vanish, so the roots of g are exactly the roots of the summands, extended by zero on the other Cartan summands; hence its root system is the orthogonal disjoint union Ψ1Ψm. The disjoint union of the maps φj from step 1.3 is therefore an isomorphism from Φ onto this root system. The direct sum is finite-dimensional and semisimple, and if Φ is irreducible then m=1 and g=g(A1) is simple.

L1L3step 1.3algebraA1

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