Alphabeta Math
TheoremStatement: AI-adaptedProof: AI-adaptedprecheck passaudited 2026-08-13
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Expectation preserves pointwise order and lies between the minimum and maximum attained values

Statement

If X(ω)≤Y(ω) for every outcome, then E[X]≤E[Y]. Consequently, for a real random variable X, min⁡ω∈ΩX(ω)≤E[X]≤max⁡ω∈ΩX(ω). In particular some outcome has value at least E[X], and some outcome has value at most E[X].

Facts & Assumptions

Given: Real random variables X,Y on a finite probability space with X≤Y pointwise.

[L1]

Expectation is the finite weighted sum of a random variable, with nonnegative weights summing to 1 (Expectation of a real random variable on a finite probability space).

[L2]

Finite sums preserve pointwise order (Laws of finite sums and finite products).

[L3]

Every nonempty finite list of reals has a maximum, and hence also a minimum by applying the maximum result to negatives (Every nonempty finite set of reals has a maximum and a minimum).

[L4]

The real numbers form a totally ordered field (The reals form a totally ordered field).

Proof

technique · direct
1.1

Nonnegative weights give X(ω)w(ω)≤Y(ω)w(ω) for every ω, so summing gives E[X]≤E[Y].

L1L2
1.2

The outcome set is nonempty because its nonnegative weights sum to 1; let m and M be the minimum and maximum of the attained values of X.

L1L3choose
2.1

The pointwise inequalities m≤X≤M and step 1.1 give m≤E[X]≤M, since the expectations of the constant variables are m and M.

step 1.1step 1.2L1L4
3.1

Outcomes attaining m and M therefore supply values at most and at least the expectation, including the constant case.

step 1.2step 2.1∎

Depends on

Used by

Dependency tree · two levels

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Sources