Alphabeta Math
TheoremStatement: AI-adaptedProof: AI-adaptedPipeline-generatedprecheck passjudge pass (gpt-6-luna)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Aliased factorial columns prevent separate coefficient identification

Statement

Let cA,cB∈RF be the columns for distinct factorial effects A,B⊆[k] in a regular fraction, and suppose cA=σcB for a fixed σ∈{−1,+1}. Consider the unrestricted fixed-design linear model Y=Xβ+ϵ, where these columns occur in X and the distribution of the error vector ϵ does not depend on β. A coefficient combination is identifiable if it has the same value for all parameter vectors giving the same distribution of Y. The contribution of these two columns depends only on σβA+βB; neither coefficient is separately identifiable while the parameter space remains unrestricted. For equal columns (σ=+1), the relevant combination is the sum; for opposite columns (σ=−1), it is the difference. Additional runs can remove the ambiguity only if they break the column relation, and hierarchy or sparsity restrictions are extra modeling assumptions.

Facts & Assumptions

Given: A regular fraction with distinct effects A,B, design columns cA,cB satisfying cA=σcB, and the fixed-design model and error-law condition in the Statement.

[F1]

Regular two-level fractions, signed defining relations, and resolution: signed-alias columns satisfy xA=σxB on every run in the fraction; sign +1 is equality and sign −1 is opposition.

Proof

technique · exhibit the coefficient combination in the fitted vector and a parameter direction that leaves it unchanged
1.1givenF1algebra

The two terms in the fitted vector combine as βAcA+βBcB=βA(σcB)+βBcB=(σβA+βB)cB. Thus the fitted vector depends on this pair only through σβA+βB, with all other coefficients fixed.

2.1givenstep 1.1algebra∎

For any t∈R, replace βA by βA+t and βB by βB−σt. Then σ(βA+t)+(βB−σt)=σβA+βB, so the combination in step 1.1 and therefore Xβ are unchanged. Because the error law is independent of β, the resulting response distributions are identical. Taking t≠0 changes both coefficients, proving that neither is separately identifiable in the unrestricted model.

Sources

Oehlert §18.6 and NIST/SEMATECH §5.3.3.4.3 explain the ambiguity left by aliased effects and the extra role of sparsity assumptions. The parameter nonidentifiability argument is given explicitly above.

Depends on

Used by

Dependency tree · two levels

2 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources