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The sectional forward-Euler step is positive and conserves augmented mass

Statement

For a nonnegative finite sectional state, if hΛi(n)≤1 for every bin, the successful step of Forward Euler for a finite sectional balance with a positivity CFL has ni+≥0, L+≥0, and

∑ixini++L+=∑ixini+L.

Facts & Assumptions

Given: A valid grid state ni,L≥0, a step h>0, and the CFL inequalities in the Statement.

[F1]

Forward Euler for a finite sectional balance with a positivity CFL: the update is (n+,L+)=(n,L)+hF(n,L) and Λi(n)=∑jKijnj+βi.

[F2]
[F3]

Finite sectional coagulation-fragmentation balance with reported overflow: each ordered pair has rate Kijninj/2 and removes both parents; fragmentation removes its parent at rate βini; retained gains are nonnegative, and overflow adds its consumed mass to L.

Proof

1.1givenF1F3algebra

For each bin, write Fi(n)=Gi(n)−niΛi(n), where Gi(n)≥0 is the total birth rate. This is the event decomposition of [F3]: the total aggregation loss of parent i is ni∑jKijnj under the ordered-pair convention, and its fragmentation loss is βini. Thus ni+=ni(1−hΛi(n))+hGi(n)≥0 by the CFL condition.

2.1givenF1F2F3algebra∎

By [F3], the reservoir update adds h times a nonnegative overflow-mass rate, so L+≥0. By [F2], the mass derivative at every nonnegative initial state is zero, so the vector-field increment has zero augmented mass; multiplying by h and adding the unchanged initial mass proves the displayed identity.

Depends on

Used by

Cited to discharge well-definedness by Forward Euler for a finite sectional balance with a positivity CFL.

Dependency tree · two levels

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Sources