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TheoremStatement: Literature-sourcedProof: AI-adaptedSession-authored (Fable 5 assisted)precheck passjudge pass (gpt-5.6-terra)audited 2026-08-28
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The radicals in a minimal primary decomposition are intrinsic

Statement

Let R be a Noetherian commutative ring, let M be a finitely generated left R-module, and let NM. Let N=Q1Qr be a minimal primary decomposition in which each Qi is pi-primary for a prime ideal pi. Then the set of component radicals is uniquely determined by M/N and equals

AssR(M/N).

Facts & Assumptions

Given: A Noetherian commutative ring R, a finitely generated left R-module M, a submodule NM, and a minimal primary decomposition N=Q1Qr with each Qi pi-primary for a prime ideal pi.

[L1]

In the Noetherian finite-module setting, if a minimal primary decomposition has each component pi-primary for a prime ideal pi, then its radicals are exactly the associated primes of the quotient (The radicals in a minimal primary decomposition are exactly the associated primes of the quotient).

Proof

technique · direct
1.1

For the given minimal primary decomposition, [L1] gives {p1,,pr}=AssR(M/N).

L1given
2.1

The right-hand side depends only on the quotient M/N, not on the chosen decomposition. Hence the set of component radicals is intrinsic.

step 1.1

Depends on

Used by

Dependency tree · two levels

5 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources