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TheoremStatement: Literature-sourcedProof: AI-adaptedverified 2026-09-23 (gpt-6-sol)
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The radicals in a minimal primary decomposition are intrinsic

Statement

Assume the Axiom of Choice.

Let R be a Noetherian commutative ring, let M be a finitely generated left R-module, and let N⊆M. Let N=Q1∩⋯∩Qr be a minimal primary decomposition in which each Qi is pi-primary for a prime ideal pi. Then the set of component radicals is uniquely determined by M/N and equals Ass⁡R(M/N).

Facts & Assumptions

Given: The Axiom of Choice (The Axiom of Choice); a Noetherian commutative ring R, a finitely generated left R-module M, a submodule N⊆M, and a minimal primary decomposition N=Q1∩⋯∩Qr with each Qi pi-primary for a prime ideal pi.

[L1]

Under the Axiom of Choice, in the Noetherian finite-module setting, if a minimal primary decomposition has each component pi-primary for a prime ideal pi, then its radicals are exactly the associated primes of the quotient (The radicals in a minimal primary decomposition are exactly the associated primes of the quotient).

Proof

technique · direct
1.1L1given

For the given minimal primary decomposition, [L1] gives {p1,…,pr}=Ass⁡R(M/N).

2.1step 1.1∎

The right-hand side depends only on the quotient M/N, not on the chosen decomposition. Hence the set of component radicals is intrinsic.

Depends on

Used by

Dependency tree · two levels

7 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources