Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-generatedprecheck passjudge pass (gpt-5.6-terra)audited 2026-09-05
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Disjoint groups of an independent sigma-algebra family remain independent

Statement

Let (Fi)iI be an independent family of sigma-algebras on a probability space, and let J0,,Jm1I be pairwise disjoint index sets. For each r<m, define

Gr:=σ(iJrFi).

Then the sigma-algebras G0,,Gm1 are independent.

Facts & Assumptions

Given: An independent family (Fi)iI and pairwise disjoint index sets J0,,Jm1.

[L1]

Independence of sigma-algebras means finite intersections of events from distinct member sigma-algebras satisfy the product formula. (Independent sigma-algebras and independent events)

[L2]

Independent pi-systems containing the whole space generate independent sigma-algebras. (Independent pi-systems generate independent sigma-algebras)

Proof

technique · direct
1.1

For each r<m, let Πr be the class consisting of Ω together with all finite intersections iFAi, where FJr is finite and AiFi for every iF. Each Πr contains Ω and is closed under finite intersections, so it is a pi-system. Moreover σ(Πr)=Gr by definition of Gr.

given
1.2

Fix CrΠr for each r<m. Because the index sets Jr are pairwise disjoint, the event r<mCr is a finite intersection of events taken from distinct members of the original independent family. Hence [L1] gives P(r<mCr)=r<mP(Cr).

givenL1
2.1

Step 1.2 says that the pi-systems Π0,,Πm1 are independent. Applying [L2] and using step 1.1 yields independence of σ(Πr)=Gr for every r<m.

L2step 1.1step 1.2

Depends on

Used by

Dependency tree · two levels

6 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources