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TheoremStatement: AI-adaptedProof: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-07
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Hopf boundary point lemma for the laplacian

Statement

Let n≥2, let Ω⊆Rn be open, and suppose BR(a)⊂Ω is an interior tangent ball at p∈∂Ω. Let u∈C2(Ω) be subharmonic, with a continuous extension to B‾R(a), such that u(x)<M for every x∈Ω and u(p)=M. If the finite derivative ∂νu(p) exists for ν=(p−a)/R, then ∂νu(p)>0.

Facts & Assumptions

Given: The objects and hypotheses in the statement.

[F1]

The exponential annulus barrier is subharmonic, has inner value one and outer value zero, and has strictly negative outward derivative. (Interior sphere barrier for the laplacian).

[F2]

The weak maximum principle controls a subharmonic function on a bounded nonempty open set by its boundary values when it is continuous on the closure. (Weak maximum principle for the laplacian).

[F4]

A continuous real function on a nonempty compact metric space attains a minimum (A continuous real-valued function on a nonempty compact metric space is bounded and attains a greatest and a least value).

[F5]

A connected space has no separation into two nonempty disjoint open subsets (Separation of a topological space, connected and disconnected spaces, clopen sets, and connected subsets).

Proof

technique · direct
1.1F1given

On the compact inner sphere, continuity and strict inequality give ε=M−max⁡∣x−a∣=R/2u(x)>0. Take the exponential barrier v, equal to one on that sphere and zero on the outer sphere.

1.2F5givenalgebra

Here is the additional Hopf route to the strong subharmonic principle. Suppose U is a domain and f∈C2(U) satisfies Δf≥0 and f≤M in U, and E={f=M} is nonempty but not all of U. It is relatively closed. Its complement G is nonempty open, and some y∈E is a relative boundary point of G; otherwise E and G would separate U. Choose d>0 with B‾d(y)⊂U and x∈G with ∣x−y∣<d/4.

2.1F1F2step 1.1

Continuity from inside the tangent ball gives u≤M on its entire outer sphere. On the annulus, w=u+εv−M is subharmonic and continuous on the closure, and its values are at most zero on both boundary spheres. The weak maximum principle gives w≤0 throughout the annulus.

2.2F3F4step 1.2algebra

Set r=inf⁡z∈E∣x−z∣. Openness of G gives r>0, and r≤∣x−y∣<d/4. A closest point q∈E exists: minimize distance on the nonempty compact set E∩B‾d/2(y); points of E outside this set have distance from x greater than d/4, so this also minimizes over all of E. The ball Br(x) lies in G, its closure lies in U, and q is on its sphere.

3.1F1step 2.1algebra

For 0<t<R/2, u(p)−u(p−tν)≥εv(p−tν). Divide by t>0 and pass to the assumed finite limit: ∂νu(p)≥−ε∂νv(p)>0.

4.1step 3.1step 2.2algebra∎

Apply the boundary conclusion already proved in step 3.1 to f on G, with this tangent ball and boundary point q. It gives a positive outward derivative. But q∈U is an interior maximum of the differentiable function f, so all its first derivatives are zero and this directional derivative is zero. Therefore E=U and f is constant. This alternative uses no mean inequality.

Depends on

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