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TheoremStatement: Literature-sourcedProof: AI-generatedprecheck passverified 2026-09-24 (gpt-6-sol)
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Hyperbolicity of a finitely generated group is independent of the finite generating set

Statement

Assume the Axiom of Choice. Let G be a finitely generated group. If the Cayley graph of G is hyperbolic for one finite generating set, then it is hyperbolic for every finite generating set.

Facts & Assumptions

Given: AC, a finitely generated group G and two finite generating sets S,T.

[L1]

Two finite generating sets of a group give bilipschitz equivalent word metrics (The identity map between the word metrics of two finite generating sets is a bilipschitz equivalence).

[L2]

Hyperbolicity is a quasi-isometry invariant of geodesic spaces (Hyperbolicity is a quasi-isometry invariant of geodesic spaces).

[A1]

AC is used in [L2] through its Morse and controlled-inverse suppliers (The Axiom of Choice).

Proof

technique · direct
1.1givenL1

By [L1], the identity map on the vertex sets is bilipschitz for the two word metrics. Extend it over each edge of Γ(G,S) by a chosen shortest T-path for that edge label, and conversely for T-edges. Because the generating sets are finite, these paths can be fixed by finitely many choices. The resulting maps are quasi-isometries of the geometric Cayley graphs: every point is within 1/2 of a vertex, and the vertex metrics have the bilipschitz bounds from [L1].

2.1L2A1step 1.1∎

By [L2], under [A1] hyperbolicity transfers from one geometric Cayley graph to the other. Since S,T were arbitrary finite generating sets, the definition does not depend on the set.

Depends on

Used by

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Dependency tree · two levels

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