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Forcing residuals determine local inexact-Newton rates

Statement

Let n≥0 be an integer, let U⊆Rn be open, let F:U→Rn be C1, and let x∗∈U satisfy F(x∗)=0 with J∗:=DF(x∗) invertible. Suppose J=DF is L-Lipschitz on a closed ball of positive radius about x∗ contained in U. Fix ηˉ∈[0,1). For n=0 use the zero operator-norm convention of An inexact Newton residual gives a local error recurrence. Consider any sequence xk+1=xk+pk,J(xk)pk+F(xk)=rk,∥rk∥2≤ηk∥F(xk)∥2, with 0≤ηk≤ηˉ. Define ∥v∥∗:=∥J∗v∥2. There is ρ>0 such that, if ∥x0−x∗∥∗≤ρ, every iterate remains in the ball and ∥xk−x∗∥∗≤qk∥x0−x∗∥∗ for some q<1. Consequently:

  1. If ηk→0, the iterates converge superlinearly (unless an exact root is reached, in which case the exact recurrence remains there).
  2. If ηk≤Cη∥F(xk)∥2 for a constant Cη, the iterates converge quadratically.

The fixed bound ηˉ<1 gives linear convergence. Since J∗ is invertible, these rates in ∥⋅∥∗ are equivalent to the same local rates in the Euclidean norm. For F=∇f with f∈C2(U) (all ordered partial derivatives through order two exist and are continuous), J(x)=∇2f(x), so the residual is the inexact Newton residual ∇2f(xk)pk+∇f(xk), using the Hessian convention of The Hessian matrix and critical points of a scalar field. This theorem concerns the unshifted full-step recurrence; it does not assert that a safeguarded line-search algorithm eventually selects that branch.

Facts & Assumptions

Given: U,F,x∗,J,J∗,L,ηˉ,(xk),(pk),(rk),(ηk) and the hypotheses in the Statement.

[F1]

An inexact Newton residual gives a local error recurrence: in a sufficiently small ball, ∥F(x)∥2≤CF∥x−x∗∥∗ and ∥x+p−x∗∥∗≤(η+C∥x−x∗∥∗)∥x−x∗∥∗ whenever J(x)p+F(x)=r and ∥r∥2≤η∥F(x)∥2.

[F3]

The Hessian matrix and critical points of a scalar field: for a scalar field, the Hessian is the matrix of second partial derivatives; the gradient is defined from first partials by The Jacobian matrix of partial derivatives and the gradient in the scalar-valued case.

[F4]

A total derivative computes every directional derivative, and its matrix is the Jacobian: the matrix of a total derivative is the Jacobian, with column j equal to the jth partial derivative.

[F6]

Continuous mixed partials of order k are invariant under permutations: for a Ck scalar field, k≥2, every iterated derivative of order k is unchanged by permutations of its coordinate differentiations.

Proof

Given: The hypotheses and notation in the Statement.

1.1givenalgebra

If n=0, every iterate, residual and correction is the unique zero vector and xk=x∗ for all k. Choose any ρ>0 and q=(1+ηˉ)/2<1; all error bounds are 0≤0. The exact-root alternative applies from the start, including the quadratic zero-error bound. For the remainder assume n≥1.

1.2givenF1choosealgebra

Let CF,C and a radius r0 be supplied by [F1], and let K∗:=∥J∗−1∥op. Set q:=(1+ηˉ)/2<1. Choose ρ>0 with K∗ρ≤r0 and, when C>0, Cρ≤(1−ηˉ)/2.

2.1givenF1step 1.2induction

Suppose ∥xk−x∗∥∗≤ρ. Then ∥xk−x∗∥2≤K∗ρ≤r0, so [F1] applies and gives ∥xk+1−x∗∥∗≤(ηk+C∥xk−x∗∥∗)∥xk−x∗∥∗≤q∥xk−x∗∥∗≤ρ. Induction proves every iterate remains in the ball and the geometric bound.

3.1givenF1F2step 2.1algebra

By [F2] and step 2.1, ∥xk−x∗∥∗→0. If xk≠x∗, divide the recurrence in [F1] by ∥xk−x∗∥∗ to get ∥xk+1−x∗∥∗∥xk−x∗∥∗≤ηk+C∥xk−x∗∥∗. When ηk→0, the right side tends to zero. If some xk=x∗, then F(xk)=0 and the residual bound gives rk=0; local invertibility in [F1] forces pk=0, so all later iterates remain there.

3.2givenF1step 2.1algebra

If ηk≤Cη∥F(xk)∥2, [F1] and step 2.1 yield ∥xk+1−x∗∥∗≤(CηCF+C)∥xk−x∗∥∗2, which is quadratic convergence in the ∗ norm.

4.1givenF3F4F5F6step 2.1algebra∎

In the specialization F=∇f with f∈C2(U), each Fi=∂if has continuous first partials. By [F5] it is totally differentiable, and by [F4] the matrix of DF has entries Jij=∂j(∂if). By [F6] these equal ∂i(∂jf), the entries of the Hessian in [F3]. Thus J(x)=∇2f(x). Invertibility gives K∗−1∥e∥2≤∥e∥∗≤∥J∗∥op∥e∥2 for every e. These fixed comparison constants transfer the linear, superlinear, and quadratic bounds from the ∗ norm to the Euclidean norm. The fixed-ηˉ geometric estimate of step 2.1 is linear convergence.

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