Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedverified 2026-10-22 (gpt-6.1-sol)
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

State similarity preserves input-output data

Statement

Let d≥0, m,p≥1, and q≥1 be integers. Suppose a noiseless experiment has matrices A∈Md×d(R), B∈Md×m(R), and C∈Mp×d(R), initial state x0∈Rd, and common inputs (uk)0≤k<q−1. For any invertible T∈Md(R) define A^=T−1AT,B^=T−1B,C^=CT,x^0=T−1x0. The experiment with (A^,B^,C^,x^0) and the same inputs has the same output yk at every sample 0≤k<q. The equality holds for every horizon and every common input sequence.

Facts & Assumptions

Given: A noiseless real discrete experiment of horizon q, matrices A,B,C, initial state x0, common inputs u0,…,uq−2, and an invertible matrix T∈Md(R).

[F1]

Discrete linear input-state-output experiments: the state and output equations are xk+1=Axk+Buk and yk=Cxk at the stated samples.

[F2]

Invertible matrices and the general linear group GL⁡n(F): an invertible T has a two-sided inverse T−1, so TT−1=T−1T=Id.

[F3]

Matrix multiplication is associative, unital, distributive, and compatible with scalar multiplication: conformable matrix products are associative and identity matrices act on either side.

Proof

1.1givenF1F2F3algebra

At k=0, the transformed initial state is x^0=T−1x0. If x^k=T−1xk for k<q−1, then [F1] and the definitions give x^k+1=A^x^k+B^uk=T−1ATT−1xk+T−1Buk=T−1(Axk+Buk)=T−1xk+1; [F2] cancels TT−1 and [F3] permits regrouping. Induction proves x^k=T−1xk for 0≤k<q.

2.1givenF1F2step 1.1algebra∎

For every such k, the transformed output is y^k=C^x^k=CTT−1xk=Cxk=yk by [F1] and [F2]. Since the horizon, initial state, and inputs were arbitrary, this holds for every common finite input experiment.

Coordinate diagram

The square records the state-coordinate identity T−1A=A^T−1: both paths send x to T−1Ax. The proof above establishes the output identity by induction and does not rely on the diagram.

RdRdRdRdAT¡1T¡1bA

Depends on

Used by

Dependency tree · two levels

9 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources