Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedjudge pass (gpt-6-luna)
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Isotropic ridgeless least-squares risk on both sides of interpolation

Statement

Assume the Axiom of Choice. Let (ξij)i,j≥1 be one infinite iid array of real random variables with mean zero, variance one, and finite fourth moment. Let pn≥1 with pn/n→γ∈(0,∞)∖{1}, and let Xn=(ξij)1≤i≤n, 1≤j≤pn be its upper-left block. Let βn∈Rpn be deterministic with ∥βn∥2=r for a fixed r≥0. Let εn have independent centered components of variance σ2, independent of Xn, and let z0,n be independent of (Xn,εn), centered, and have covariance Ipn. Set yn=Xnβn+εn, β^n=Xn+yn, and define the design-conditional prediction risk Rn:=Eεn,z0,n[(z0,nT(β^n−βn))2∣Xn]. Then almost surely Rn⟶{σ2γ1−γ,0<γ<1,r2(1−1γ)+σ2γ−1,γ>1. This result gives no limit assertion for sequences with pn/n→1.

Facts & Assumptions

Given: The nested real iid design, pn/n→γ≠1, fixed signal norm r≥0, independent centered noise with covariance σ2In, centered test features with covariance Ipn, and the Axiom of Choice.

[A1]

The Axiom of Choice permits a choice function for every family of nonempty sets (The Axiom of Choice).

[F1]

For the nested real iid finite-fourth-moment model with fixed signal norm r>0 and the same noise and test-feature assumptions, the almost-sure risk limits are σ2γ/(1−γ) for γ<1 and r2(1−1/γ)+σ2/(γ−1) for γ>1 (Isotropic minimum-norm risk limits under a positive spectral gap).

[F2]

When r=0, the same model has almost-sure risk limits σ2γ/(1−γ) for γ<1 and σ2/(γ−1) for γ>1 (Isotropic ridgeless risk limit when the signal is zero).

[F3]

The estimator Xn+yn is the ridgeless minimum-norm least-squares estimator (Ridgeless minimum-norm least-squares regression).

[F4]

Iid entries are independent and share one common distribution (Identical distribution and IID families).

Proof

1.1givenA1F1F4

If r>0, the design, signal, noise, and test-feature hypotheses in the Statement are exactly those of [F1]; [F4] fixes the iid convention and [A1] supplies its choice assumption, so the two limits apply.

1.2givenA1F2F4algebra

If r=0, then βn=0 for every n, and [F2] gives the limits in the Statement under [A1] and the iid convention [F4].

2.1givenF3step 1.1step 1.2algebra∎

Since r≥0, the cases in steps 1.1 and 1.2 exhaust the signal norms. The estimator and conditional risk are those defined in [F3], so the resulting limits are precisely the displayed formula.

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