Alphabeta Math
LemmaStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedjudge pass (gpt-6-luna)
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  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
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Separate isotropic ridgeless risk into limiting bias and variance

Statement

Under the hypotheses and notation of the isotropic ridgeless risk theorem, put Sn=XnTXn/n, Bn:=∥(Ipn−Xn+Xn)βn∥22,Vn:=σ2ntr⁡(Sn+). Then almost surely, if 0<γ<1, Bn⟶0,Vn⟶σ2γ1−γ, and if γ>1, Bn⟶r2(1−1γ),Vn⟶σ2γ−1.

Facts & Assumptions

Given: The model, parameters, and risk notation in the Statement.

[F1]

The exact conditional risk is Rn=Bn+Vn (Exact bias and noise decomposition of isotropic prediction risk).

[F2]

For zero signal, the risk equals Vn and has the limits stated in the zero-signal lemma (Isotropic ridgeless risk limit when the signal is zero).

[F3]

The total risk has the two limits in the isotropic ridgeless risk theorem (Isotropic ridgeless least-squares risk on both sides of interpolation).

Proof

1.1F1F2algebra

By [F1], for every n the risk decomposes exactly as Rn=Bn+Vn. For the zero signal the bias term is zero, so the zero-signal risk is exactly this same design-dependent Vn; [F2] therefore gives the almost-sure limits of Vn.

2.1F2F3step 1.1algebra∎

If γ<1, [F3] and [F2] give the same limit for Rn and Vn, so their difference Bn tends to zero. If γ>1, subtracting σ2/(γ−1), the limit of Vn in [F2], from the total-risk limit in [F3] leaves r2(1−1/γ) for Bn. The probability-one events in [F2] and [F3] may be intersected.

Depends on

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Sources