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Cover-El Gamal-Salehi sufficient condition for correlated sources over a DM-MAC

Statement

Let (S1,S2) be finite and let its IID copies be transmitted losslessly over the DM-MAC of Two-user discrete memoryless multiple-access channel using the separate encoders of Lossless transmission of two correlated IID sources over a DM-MAC. If there is a finite Q independent of (S1,S2) and a law PQPS1S2PX1∣S1,QPX2∣S2,QWY∣X1X2 such that H(S1∣S2)<I(X1;Y∣X2,S2,Q),H(S2∣S1)<I(X2;Y∣X1,S1,Q),H(S1,S2)<I(X1,X2;Y∣Q), then the two correlated IID sources can be transmitted with vanishing average joint error. This is a sufficient condition only; it is not a general capacity characterization for correlated sources over a DM-MAC.

Facts & Assumptions

Given: Finite source and channel alphabets, IID source pair (S1,S2), a memoryless DM-MAC, and a finite law of the displayed product-kernel form.

[F1]

Lossless transmission of two correlated IID sources over a DM-MAC: each encoder observes its own source block only, the common decoder reconstructs both blocks, and reliability means average joint error tends to zero.

[F2]

Two-user discrete memoryless multiple-access channel: conditional on both input words, the output law is the product of the kernel W(y∣x1,x2).

[F3]

Conditional type packing bounds for source-indexed DM-MAC codebooks: for the source-indexed conditional codebooks, the expected wrong single-source and wrong source-pair typical candidates vanish under the three strict conditional-entropy/mutual-information inequalities.

[F4]

Finite conditional entropy: conditional entropy is the finite average of the conditional entropies over positive-mass conditioning values.

[F5]

Finite mutual information: finite mutual information is the joint-to-product KL sum in nats.

[F6]

Finite conditional mutual information: finite conditional mutual information averages the conditional informations over positive-mass conditioning values.

[F7]

Finite conditional mutual information identities and equality: conditional mutual information is the corresponding conditional entropy difference for finite variables.

Proof

1.1givenF1chooseconstruct

Fix a law and a rate-independent public schedule qn whose empirical distribution tends to PQ; choose symbol counts by rounding nPQ(q) and distributing the bounded remainder. For every s1n, independently draw a codeword with law ∏iPX1∣S1,Q(⋅∣s1i,qi), and for every s2n independently draw a codeword with law ∏iPX2∣S2,Q(⋅∣s2i,qi). The two codebooks and all their indexed entries are independent.

2.1F1F2step 1.1construct

Encoder j observing sjn sends the codeword indexed by that exact source sequence. Fix one default pair of source blocks from the nonempty finite source alphabets. The decoder returns the unique pair (s^1n,s^2n) for which (qn,s^1n,s^2n,x1n(s^1n),x2n(s^2n),yn) is jointly strongly typical for the displayed law when exactly one pair passes; if zero or multiple pairs pass, it returns the fixed default pair. These maps have the interfaces in [F1] and the output law in [F2].

2.2F1F2step 1.1algebra

Conditional on qn, the random tuples (S1i,S2i,X1i(S1n),X2i(S2n),Yi) are independent across i in the codebook ensemble. For each fixed joint letter, the empirical frequency has variance at most 1/(4n) and mean equal to the qn-type average of its conditional probability. That mean tends to the target probability because the type of qn tends to PQ. Chebyshev's inequality and a union bound over the finite alphabet show that the true tuple is support-restricted jointly typical with probability tending to one; target-zero letters never occur because every source, encoder and channel kernel is used only on its support.

3.1F3F4F5F6F7step 2.2algebraalgebra

On the event that the true tuple is typical, a decoding error can occur only if some wrong candidate differs in source 1 alone, source 2 alone, or both. The strict hypotheses are finite conditional-entropy and mutual-information inequalities by [F4]–[F7]; they let us choose the typicality tolerance so that each exponent in [F3] is positive. Therefore the conditional expected number of wrong typical candidates tends to zero; Markov's inequality makes the probability of any such candidate tend to zero. Combining with step 2.2 proves that the ensemble-average source-block error tends to zero.

4.1F1step 3.1choose∎

At each n the alphabets and source-indexed codebooks are finite, so the random ensemble has finite support. At least one deterministic codebook realization has error no larger than the ensemble mean. Fixing such realizations along increasing blocklengths gives the deterministic reliable codes required by [F1]. Taking the closure of the strict region completes the sufficient-condition proof; no converse or necessity claim is made.

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