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TheoremStatement: Literature-sourcedProof: AI-adaptedprecheck passaudited 2026-09-14
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James space is complete and separable

Statement

The real James space J is a separable Banach space. Its standard unit vectors (en)n≥1 form a Schauder basis, and the coordinate truncations ΠNx=(x1,…,xN,0,…) satisfy

∥ΠNx∥J≤∥x∥J,∥x−ΠNx∥J≤∥x∥J,∥x−ΠNx∥J⟶0.

Facts & Assumptions

[L0]

James coordinate n≥1 is the underlying c0 coordinate n−1, and en is supported at that coordinate (James space).

[L1]

The James formula is a norm, dominates the supremum norm, and satisfies ∥x∥J≤2∥x∥2 on ℓ2 (The James formula defines a norm).

[L2]

Real c0 is complete for the supremum norm (Real and complex c0 are Banach).

[L3]

A Schauder basis requires existence and uniqueness of the norm-convergent coordinate expansion (Schauder basis and coordinate functionals).

Proof

technique · direct

Given: The objects and hypotheses in the Statement.

1.1L1L2algebra

Let (x(m)) be Cauchy in J. By [L1] it is Cauchy in c0, so [L2] [given, L1, L2] gives x(m)→x∈c0 uniformly. For each fixed tuple p, qp(x)=lim⁡mqp(x(m)), whence sup⁡pqp(x)<∞. Letting m→∞ in qp(x(n)−x(m))<ε uniformly in p yields ∥x(n)−x∥J≤ε. Thus J is complete.

2.1givenL0L1step 1.1

For p=(p1<⋯<pk) in the positive labeling of [L0], define the auxiliary endpoint variation

rp(x)2=12(∣xp1∣2+∑j<k∣xpj−xpj+1∣2+∣xpk∣2)

(with r(p1)(x)=∣xp1∣), and R(x)=sup⁡prp(x). Direct expansion gives ∥x∥J≤2R(x). Appending an index m→∞ to p and using xm→0 gives rp(x)≤∥x∥J. Hence 2−1/2∥x∥J≤R(x)≤∥x∥J. [L1, endpoint expansion]

3.1givenstep 2.1

Finite-support sequences are dense. Indeed, for nonzero x and ε>0, choose δ>0 with 4δR(x)<ε2. Choose a tuple p with rp(x)>R(x)−δ, append a sufficiently remote final index N=pk so this remains true, and ensure sup⁡i≥N∣xi∣<δ. Put ξ=ΠNx. For any tuple q meeting the tail, delete its indices at most N and call the remaining tuple q′. Concatenating p and q′ in the definition of R(x) gives

R(x)2>(R(x)−δ)2−δ2+rq′(x)2,rq′(x)2<2δR(x).

Thus R(x−ξ)2<2δR(x), and step 2.1 gives ∥x−ξ∥J2<4δR(x)<ε2. The zero vector is already finite support. [step 2.1, finite concatenation, x∈c0]

4.1step 2.1algebra

Fix a tuple q. If it lies wholly before or after N, the two [given, step 2.1, step 3.1] contractive estimates for ΠNx and x−ΠNx are immediate. If it crosses N, delete respectively the tail or the head. Expanding the one new jump to zero shows that the resulting q-variation equals an auxiliary endpoint variation rq′(x), hence is at most R(x)≤∥x∥J by step 2.1. Taking suprema proves both contractive inequalities.

5.1L0L3step 3.14.1

Given x and ε>0, step 3.1 gives finite-support u with [given, L0, L3, step 3.1, step 4.1] ∥x−u∥J<ε. For N beyond its support, step 4.1 gives ∥x−ΠNx∥J=∥(I−ΠN)(x−u)∥J≤∥x−u∥J<ε. Coordinatewise uniqueness in the labeling of [L0] is immediate, so [L3] makes (en) a Schauder basis.

6.1step 3.1algebra∎

Finite-support sequences with rational coordinates form a countable set. [given, step 3.1, step 5.1] They are dense by step 3.1 and finite-dimensional rational approximation, so J is separable.

Depends on

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Sources