Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedjudge pass (gpt-5.6-terra)audited 2026-09-12
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Kac moody verma module has a unique simple quotient

Statement

For any weight λ of a finite generalized Cartan matrix over C, the Verma module MA(λ) has a unique maximal proper submodule Nλ. The quotient LA(λ)=MA(λ)/Nλ is nonzero, simple and highest weight λ. Every simple module generated by a nonzero highest vector of weight λ is isomorphic to this quotient.

Facts & Assumptions

Given: The Verma module and its highest vector vλ=11.

[F1]

Universality, O membership, and the one-dimensional top space follow from Universal property and pbw character of kac moody verma modules.

[F2]

Submodules and quotients of O modules are weight modules, with their corresponding weight intersections and quotients (Kac moody category o).

Proof

1.1

A submodule N is a sum of its weight intersections by F2. Explicitly, for a finite weight sum x=j=1rxμjN, choose hh with all μj(h) distinct. Such an h exists: in a finite basis h1,,hd, the curve h(t)=a=1dta1ha makes each nonzero difference (μjμl)(h(t)) a nonzero polynomial, and finitely many such polynomials exclude only finitely many complex t. Applying lj(hμl(h))/(μj(h)μl(h)) to x gives xμjN. If N has nonzero top space, it contains vλ because that space is one dimensional; since vλ generates MA(λ), then N=MA(λ).

F1F2given
2.1

Form the algebraic sum Nλ of all proper submodules, meaning all finite sums of their elements. This is a submodule. Each summand has zero top component by 1.1, so every such finite sum has zero top component. Thus Nλ is proper and contains every proper submodule. A strictly larger submodule must be the whole module, proving both maximality and uniqueness. Its quotient is nonzero since the top vector survives; any proper nonzero submodule of the quotient would lift to a submodule strictly between Nλ and the whole module, which is impossible. The surviving top vector generates the quotient, so it is simple highest weight λ.

step 1.1given
3.1

If a simple module V has a specified nonzero highest vector of weight λ, F1 supplies a map MA(λ)V whose image is the cyclic submodule generated by that vector, hence all of V. Its kernel is maximal proper, because an intermediate submodule would give a nonzero proper submodule of V. By 2.1 this kernel is Nλ, giving the stated isomorphism. If MA(λ) itself is simple, the sum in 2.1 is just zero and the same construction applies. Finite interpolation includes the single-weight case with empty product 1. No Zorn argument, arbitrary family of choices or finite-dimensionality of the whole module is used.

F1step 1.1step 2.1

Depends on

Used by

Dependency tree · two levels

7 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources