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TheoremStatement: AI-adaptedProof: AI-generatedprecheck passaudited 2026-08-30
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Every L^1 function admits dominated complex simple approximations

Statement

Let (X,A,μ) be a measure space and let fL1(μ). Then there exists a sequence (sn) of complex simple functions such that:

  1. sn2f for every n;
  2. fsndμ0.

Facts & Assumptions

Given: A measure space (X,A,μ) and an integrable function f:XC.

[L1]

An integrable complex function has measurable real and imaginary parts and integrable modulus. (Integrable real and complex functions, and their integrals)

[L2]

The positive and negative parts satisfy u=u+u and u=u++u. (The positive and negative parts of a function)

[L3]

Arithmetic and lattice operations preserve measurability. (Arithmetic and lattice operations preserve measurability whenever they are defined)

[L4]

Every nonnegative measurable function admits increasing simple approximations. (Every nonnegative measurable function admits an explicit increasing sequence of simple approximations)

[L5]

Monotone convergence passes increasing limits through the integral. (Monotone convergence for the integral)

Proof

technique · direct
1.1

Write f=u+iv with u=Ref and v=Imf. [L1, L2, L3] By [L1], the real functions u and v are measurable and satisfy uf and vf, hence are integrable. By [L2] and [L3], the four functions u± and v± are nonnegative measurable.

2.1

Apply [L4] to choose increasing nonnegative simple functions [L2, L3, L4, step 1.1] un±u± and vn±v±. Put un:=un+un,vn:=vn+vn,sn:=un+ivn. Then each sn is a complex simple function, and snun++un+vn++vnu+v2f.

3.1

By [L5], the four increasing simple approximations in step 2.1 satisfy [L2, L5, step 2.1] un±dμu±dμ and vn±dμv±dμ. Therefore uundμ=(u+un+)dμ+(uun)dμ0, and similarly vvndμ0. Hence fsndμuundμ+vvndμ0.

4.1

Steps 2.1 and 3.1 give the required dominated complex simple [step 2.1, step 3.1] ∎ approximations.

Depends on

Used by

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Sources