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TheoremStatement: Literature-sourcedProof: AI-generatedprecheck passaudited 2026-09-04
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Landau's theorem for Dirichlet series with nonnegative coefficients

Statement

Let D(s)=∑n≥1ann−s with an≥0 for every n, and assume its abscissa of convergence σc is finite. Then s=σc is a singular point of the holomorphic function defined by D on ℜs>σc.

Facts & Assumptions

Given: A Dirichlet series D(s)=∑ann−s with an≥0 and finite abscissa σc.

[L1]

The abscissa is defined through right-half-plane convergence (The convergence and absolute-convergence abscissae of a Dirichlet series).

Proof

technique · contradiction
1.1L2assume-contra

Suppose D were holomorphic on a disc centered at σc. Choose a real point σ1>σc inside that disc and a radius r>σ1−σc still contained in the disc. By [L2], for every m≥0, (−1)mm!D(m)(σ1)=∑n≥1an(log⁡n)mm!n−σ1, and every coefficient on the right is nonnegative.

2.1L1step 1.1

The Taylor series of D at σ1 therefore has nonnegative coefficients: D(s)=∑m≥0cm(σ1−s)m,cm≥0. Because the disc radius exceeds σ1−σc, this series converges at some real point σ∗<σc. Evaluating there and using the displayed formula for cm gives ∑n≥1ann−σ∗<∞. So the Dirichlet series converges at σ∗, contradicting the definition of σc in [L1].

3.1step 2.1discharge-contradiction∎

Hence σc cannot be a regular point of the holomorphic continuation: it is a singular point.

Depends on

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