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TheoremStatement: AI-adaptedProof: AI-adaptedprecheck passjudge pass (gpt-5.6-terra)audited 2026-09-01
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  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
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For an R-finite module over a local map, flatness on the closed fibre plus the multiplication-map condition implies flatness

Statement

Let RS be a local homomorphism of Noetherian local rings with maximal ideal mR, and let M be a finite S-module that is also finitely generated as an R-module. Assume:

  1. the closed fibre M/mM is flat over S/mS;
  2. the multiplication map mRMM is injective.

Then M is flat over R.

Facts & Assumptions

Given: A local map of Noetherian local rings RS with maximal ideal m, and a finite S-module M that is finitely generated as an R-module and satisfies the two hypotheses.

[L1]

The ideal-form local criterion applies once one knows that M/mM is flat over R/m and that

mRMM

is injective (For an R-finite module over a local map, flatness modulo I and injectivity of IMM imply flatness).

Proof

technique · direct
1.1

The ring R/m is a field. Since M/mM is flat over the S/mS-algebra in hypothesis 1, it is in particular a vector space over R/m, hence flat over R/m.

givenalgebra
1.2

Hypothesis 2 is exactly the injectivity condition required in [L1] for the ideal I=m. Therefore [L1] applies and yields that M is flat over R.

L1given
2.1

This is the claimed closed-fibre criterion.

algebra

Depends on

Used by

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Dependency tree · two levels

7 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources