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TheoremStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedprecheck passjudge pass (gpt-6-sol)audited 2026-09-30
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Lyapunov drift bound for hitting times

Statement

Assume AC (The Axiom of Choice). Let E be at most countable with sigma-algebra 2E, let K be a probability kernel, and set p(x,y)=K(x,{y}). For each x∈E, let Px be the canonical path-space chain law with initial measure δx and transition kernel K, and let Ex be its expectation. For A⊆E, define TA=inf⁡{n≥0:Xn∈A}. If ψ:E→[0,∞) is finite-valued with Pψ(x)<∞ for every x and Lψ(x)≤−1 on E∖A, using the support-restricted kernel action and finite drift, then Ex[TA]≤ψ(x) for every x. Consequently Px(TA<∞)=1.

Facts & Assumptions

Given: AC, an at most countable state space E, a probability kernel K with transition matrix p, a target A⊆E, and a finite-valued nonnegative ψ satisfying Pψ<∞ everywhere and Lψ≤−1 on Ac.

[A1]

AC is the assumption available to construct each fixed-start canonical law and is assumed by the prior first-step and superharmonic-majorant theorems. (The Axiom of Choice)

[F1]

An at most countable set is finite or countably infinite. (Finite, countably infinite, countable, uncountable)

[F2]

A probability kernel is a probability measure in the target variable and has total mass one. (Measure kernel and probability kernel)

[F3]

For x∈E, the Dirac set function δx is a probability measure. (A Dirac set function is a probability measure)

[F4]

AC gives the canonical path-space law for a probability initial measure and a probability kernel; its coordinate process is the corresponding Markov chain. (Canonical Markov chain on path space)

[F5]

With initial state fixed at x, write Px for the law with initial distribution δx and Ex for its expectation. (Initial distribution of a Markov chain)

[F6]

TA=inf⁡{n≥0:Xn∈A}, the infimum of the empty set is +∞, and TA=0 when the start is in A. (Hitting, return, and visit times)

[F7]

The transition matrix is p(x,y)=K(x,{y}). (Transition matrices and n-step probabilities)

[F8]

For finite-valued ψ, Pψ(x)=∑y:p(x,y)>0p(x,y)ψ(y); when this is finite, Lψ(x)=Pψ(x)−ψ(x). Zero transition weights are omitted. (Nonnegative kernel action and finite drift)

[F9]

For bounded nonnegative boundary payoff f and running cost c, the first-step exit cost is u(x)=Ex[B+∑0≤m<Tc(Xm)], where B=f(XT) on T<∞ and B=0 on T=∞. (First-step equations for nonnegative exit costs)

[F10]

If D⊆E, f:Dc→[0,∞) and c:D→[0,∞) are bounded, and finite-valued ψ≥0 satisfies Pψ<∞ everywhere, ψ≥f on Dc, and Lψ≤−c on D, then the corresponding exit cost obeys u(x)≤ψ(x). (Superharmonic majorants bound exit costs)

[F11]

Expectation of a nonnegative measurable random variable is its extended nonnegative integral, and the nonnegative integral preserves pointwise order. (Expectation of a nonnegative or integrable random variable, Monotonicity and nonnegative homogeneity of the nonnegative integral)

Proof

technique · identify $T_A$ with the unit running cost up to first exit from $A^c$, then apply the superharmonic-majorant bound
1.1A1F2F3F4F5given

Fix x∈E. By [F2] and [F3], K and δx satisfy the kernel and initial-measure hypotheses of [F4]; AC [A1] therefore supplies the canonical law Px, and [F5] fixes the notation Ex. This is done for each x separately, without selecting path-space realizations as a family.

1.2F6given

Pathwise, if TA=k<∞ then exactly the indices m=0,…,k−1 satisfy m<TA, while if TA=∞ every m≥0 does; hence ∑m≥01{m<TA}=TA in [0,+∞]. In particular the sum is empty and equals zero when the starting state is in A.

1.3F1F2F7F8given

Set D=Ac, let f be the zero function on A=Dc, and let c be the constant one function on D. Both are bounded and nonnegative, ψ≥f on A, and [F8] identifies the given drift condition with Lψ≤−c on D. Countability and the matrix-kernel relationship are [F1], [F2], and [F7].

2.1F6F9step 1.2step 1.3given

For the exit problem in step 1.3, the boundary payoff is zero on both TA<∞ and TA=∞, and the accumulated running cost is ∑m<TA1. By [F9] and the pathwise identity in step 1.2, its value is u(x)=Ex[TA], including the value +∞ if the target is never hit.

3.1A1F1F8F10step 1.3step 2.1given

The hypotheses of [F10] hold for D=Ac, f=0, and c=1: the chain is countable by [F1], AC [A1] is assumed, step 1.3 verifies the boundary and drift inequalities, and Pψ is finite everywhere by hypothesis. Therefore step 2.1 and [F10] give Ex[TA]=u(x)≤ψ(x).

4.1F11step 3.1given

For each integer N≥1, pointwise N1{TA=∞}≤TA∧N≤TA. By [F11] and step 3.1, NPx(TA=∞)≤Ex[TA∧N]≤Ex[TA]≤ψ(x)<∞; letting N grow forces Px(TA=∞)=0. Thus the stated expectation bound also gives almost-sure hitting.

5.1A1F6F7F8step 1.2step 2.1step 3.1given∎

If A=E, then TA=0 and the bound is immediate. If A=∅ and E≠∅, step 2.1 would give +∞=Ex[TA]≤ψ(x)<∞, so no ψ can satisfy the hypotheses; the implication is vacuous in this case. For a one-state chain, A=E is the first case, while for A=∅ its sole row has p(x,x)=1 and Lψ(x)=0, contradicting the drift assumption. On a deterministic row p(x,y)=1, the drift inequality gives ψ(y)≤ψ(x)−1 until the hit, so nonnegativity prevents an infinite path outside A; zero-weight terms are omitted by [F8]. The endpoints TA=0 and TA=∞ were handled in steps 1.2 and 2.1. AC is used for the canonical laws and the two prior theorems, not for the pathwise identity or deterministic calculation. This is a one-way bound, not an iff claim.

Source notes

Roch, Note 24 §2 equation (4), printed/PDF p. 3, defines the boundary payoff and accumulated pre-exit cost; the complete proof of Theorem 24.4, printed/PDF p. 4, supplies the first-step cost identity. Section 3 Theorem 24.8 and its complete proof, printed/PDF p. 7 (official PDF parser lines 312–336), state the Lyapunov hitting-time bound and reduce it to Theorem 24.7 with D=Ac, f=0, and c=1. Roch assumes A proper and states a nonnegative ψ without separately requiring finite Pψ; §1 initially defines the generator for bounded functions. This item uses the earlier library superharmonic-majorant theorem, whose explicit finite-Pψ condition makes the action and drift well-defined, and handles A=E directly. No source uncertainty remains for the stated library claim.

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