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Markov's theorem for braid closures

Statement

Assume the Axiom of Choice. Let β,β′ be braids. Then β^ and β′^ are equivalent oriented links if and only if β and β′ are Markov equivalent, that is, related by a finite sequence of conjugations in a fixed braid group, stabilizations β↦βσn±1 into the next braid group, and their inverses.

Facts & Assumptions

Given: AC, braids β,β′ and the Markov moves of Markov conjugation and stabilization moves.

[F1]

Assume ACω: each single conjugation, stabilization or destabilization preserves the oriented closure up to ambient isotopy (Markov moves preserve the oriented closure up to isotopy); AC yields ACω (AC implies DC implies countable choice).

[F2]

If two closed braids are isotopic through closed braids about the axis, the braids read from them are conjugate (Braid-isotopic closed braids are conjugate).

[F3]

Assume AC: two closed braid diagrams representing the same oriented link are related by braid isotopies of closed braid diagrams, stabilizations and destabilizations, and inverses, so the braids read from them are Markov equivalent (Reidemeister moves between closed braid diagrams factor through Markov moves).

[F4]

Assume ACω: two regular diagrams represent equivalent oriented links if and only if they are related by finitely many planar isotopies and oriented Reidemeister moves (Reidemeister's theorem for oriented diagrams).

[F5]

The closure of a braid is an oriented link whose components and orientation are those of the closure construction (The closure of a geometric braid).

Proof

technique · direct
1.1F1F5given

Markov equivalence implies isotopy of closures. Let β and β′ be Markov equivalent, so there is a finite sequence of braids β=β0,β1,…,βk=β′ in which each consecutive pair is related by a conjugation, a stabilization or a destabilization. By [F1] each single step preserves the oriented closure up to ambient isotopy; composing the finitely many ambient isotopies gives an equivalence of β^ and β′^.

1.2F2F3F5

Isotopy of closures implies Markov equivalence. Conversely, assume β^ and β′^ are equivalent oriented links. If either is empty, both are empty and [F5] forces both braid strand counts to be zero; they are the unique element of B0 and hence Markov equivalent. Otherwise both strand counts are positive. Use the closed braid diagrams obtained from the closure construction applied to β and β′, and read each diagram at its original cutting ray. The braids read this way are β and β′ themselves, up to braid isotopy. Apply [F3] to these two diagrams to obtain their Markov equivalence. If a different cutting ray is used, [F2] gives a conjugate braid, which lies in the same Markov class. Thus β and β′ are Markov equivalent.

2.1F1F2F3F4step 1.1step 1.2∎

Conclusion. Steps 1.1 and 1.2 give the equivalence. AC discharges the countable-choice hypothesis of [F1] and supplies the AC hypotheses of the factorization result [F3] and the conjugacy bridge [F2]. The Reidemeister theorem [F4] is used inside [F3], rather than to identify a braid read at its original cutting ray.

Depends on

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