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Maurer--Cartan structure equation
Statement
Assume . Let be the left Maurer--Cartan form of a Lie group , with values in . Write for its componentwise exterior derivative from Finite-dimensional vector-valued forms and their exterior derivative. For vector fields , define the bracket-valued wedge by
Then the normalized left Maurer--Cartan structure equation is
The countable-choice assumption is used exactly through the supplied Maurer--Cartan, invariant-field, and tangent-bracket results.
Facts & Assumptions
Given: , a Lie group with identity , its left Maurer--Cartan form , and with the transported left-invariant-field bracket.
is countable choice. The Axiom of Countable Choice ().
Finite-dimensional vector-valued forms and their componentwise exterior derivative are defined by scalar dual evaluation. Finite-dimensional vector-valued forms and their exterior derivative.
Every is a linear isomorphism with inverse , and . Maurer--Cartan form is a pointwise isomorphism and left invariant.
The transported tangent bracket satisfies . Lie bracket on the tangent space of a Lie group.
The tangent bracket is bilinear and alternating. The tangent space at the identity is a Lie algebra.
Every has a unique smooth left-invariant extension. Left-invariant vector fields evaluate isomorphically at the identity.
For a scalar one-form , . The exterior derivative by the invariant vector-field formula.
Proof
Bilinearity of the bracket [F5] and smoothness of [F3] show in any basis of that the displayed bracket-wedge has smooth components; alternation follows by exchanging and . Thus it is a well-defined -valued two-form. Because the bracket is alternating, [F5] also gives .
Let and use their left-invariant extensions from [F6]. For every , [F2], [F7], and [F3] give because the first two functions are the constants and and [F4] identifies the bracket field. Since linear functionals separate points, .
On the same fields, step 1.1 and [F3] yield . Adding this to step 1.2 proves the structure equation on every pair of left-invariant fields.
Fix and . Put and . By [F3], and ; injectivity of gives and . Step 2.1 therefore makes the structure equation vanish on the arbitrary pair at , proving it globally.
A Lie group is nonempty. If , both two-forms are uniquely zero; if , every alternating two-form is zero and the equation again holds. Lie groups are boundaryless by convention, and no metric, nondegeneracy, or endpoint is involved. The stated is inherited through [F3], [F4], [F5], and [F6]; componentwise differentiation and the pointwise spanning argument add no choice. The theorem is one equality, not a biconditional.
Depends on
- The Axiom of Countable Choice ($\mathrm{AC}_\omega$)
- Finite-dimensional vector-valued forms and their exterior derivative
- Maurer--Cartan form is a pointwise isomorphism and left invariant
- Lie bracket on the tangent space of a Lie group
- The tangent space at the identity is a Lie algebra
- Left-invariant vector fields evaluate isomorphically at the identity
- The exterior derivative by the invariant vector-field formula
Used by
Nothing in the library uses this result yet.
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Sources
- Robert L. Bryant, An Introduction to Lie Groups and Symplectic Geometry (standard reference, not scraped)