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TheoremStatement: Literature-sourcedProof: AI-adaptedprecheck passjudge pass (deepseek-v4-pro + gpt-5.6-terra)audited 2026-08-16
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Monomial symmetric polynomials form an R-basis of the symmetric-polynomial ring

Statement

As λ ranges over partitions of length at most n, the polynomials mλ form an R-basis of R[x1,…,xn]Sym⁡n.

Facts & Assumptions

Given: A commutative ring R and a natural number n.

[L1]

The polynomial mλ is the sum of the distinct monomials whose exponent tuples lie in the permutation orbit of λ (Monomial symmetric polynomials indexed by partitions).

[L2]

A polynomial is symmetric exactly when every permutation of its variables fixes it (Symmetric polynomials as the invariants of variable permutations).

Proof

technique · direct
1.1L1algebra

Variable permutations partition the monomials into disjoint orbits, and every orbit contains exactly one weakly decreasing exponent tuple λ.

1.2L1L2

If f is symmetric, the coefficients of two monomials in the same orbit are equal, because a variable permutation carries either monomial to the other and fixes f. Since f has finite support, it is therefore a finite R-linear combination of the corresponding orbit sums mλ.

1.3L1algebra

Distinct mλ have disjoint monomial supports. Hence a finite relation ∑λcλmλ=0 has cλ=0 for every λ, by comparing the coefficient of any monomial in the orbit of λ.

2.1step 1.2step 1.3∎

Steps 1.2 and 1.3 give spanning and linear independence, respectively, so the mλ form an R-basis.

Depends on

Used by

Dependency tree · two levels

5 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources