Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-adaptedprecheck pass
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Spectrum of a symmetrically pressure-mass-preconditioned saddle system

Statement

Assume the hypotheses and Schur bounds of Pressure Schur equivalence from inf-sup, continuity, and stiffness scaling, with constants α,Λ,Cb,β>0. For γ>0, use Pγ=diag⁡(A,γMQ) from Symmetric saddle-point system, Schur complement, and block preconditioners, and set aγ=β2Λγ,bγ=Cb2αγ,λ±(s)=1±1+4s2. Let μ1,…,μm be the eigenvalues, with multiplicity, of (γMQ)−1/2S(γMQ)−1/2. Then aγ≤μj≤bγ, and the symmetric square-root-preconditioned saddle matrix has eigenvalues {λ−(μj),λ+(μj):1≤j≤m}and 1 with multiplicity n−m. Consequently its spectrum is contained in [λ−(bγ),λ−(aγ)]  ∪  {1}  ∪  [λ+(aγ),λ+(bγ)], where the eigenvalue 1 has multiplicity zero if n=m. This is a spectral estimate for the stated scaled block preconditioner, not an iteration-count or generic solver-speed claim.

Facts & Assumptions

Given: Real finite-dimensional spaces V,Q, an SPD velocity matrix A, full-row-rank constraint matrix B, pressure mass matrix MQ, and the inf-sup, continuity, and energy-equivalence hypotheses of the Schur theorem.

[F1]

The saddle matrix is K=(ABTB0), the positive Schur matrix is S=BA−1BT, and Pγ=diag⁡(A,γMQ) is the block preconditioner (Symmetric saddle-point system, Schur complement, and block preconditioners).

[F2]

The Schur quadratic form satisfies (β2/Λ)MQ≤S≤(Cb2/α)MQ (Pressure Schur equivalence from inf-sup, continuity, and stiffness scaling).

[F3]

Every self-adjoint endomorphism of a finite-dimensional real inner product space has an orthonormal eigenbasis (Real spectral theorem: a self-adjoint endomorphism of a finite-dimensional real inner product space has an orthonormal eigenbasis).

[F4]

Rank-nullity gives dim⁡V=dim⁡ker⁡T+dim⁡im⁡T for a linear map on a finite-dimensional space (Rank-nullity: dim⁡FV=nullity⁡T+rank⁡T).

Proof

1.1F1F2F3algebra

By [F3], the SPD matrices A and γMQ have symmetric positive square roots and inverse square roots. Put T=(γMQ)−1/2BA−1/2,X=Pγ−1/2KPγ−1/2=(ITTT0). Then TTT=(γMQ)−1/2S(γMQ)−1/2. Congruencing [F2] by (γMQ)−1/2 shows aγI≤TTT≤bγI. Hence TTT is positive definite and all its eigenvalues μj lie in [aγ,bγ].

2.1F1F3step 1.1algebra

By [F3], choose an orthonormal eigenbasis y1,…,ym of TTT, with eigenvalues μj>0. Set xj=TTyj/μj. Then Txj=μjyj and xiTxj=yiTTTTyjμiμj=δij, so the xj are orthonormal. On the two-dimensional space spanned by (xj,0) and (0,yj), X has matrix (1μjμj0), whose characteristic polynomial is λ2−λ−μj. Its two roots are λ−(μj) and λ+(μj).

3.1F1F4step 1.1step 2.1algebra

The matrix TTT is positive definite by step 1.1, so for every y∈Rm, x=TT(TTT)−1y satisfies Tx=y. Thus T:Rn→Rm is onto, and [F4] gives dim⁡ker⁡T=n−m. For x∈ker⁡T, X(x,0)=(x,0), giving eigenvalue 1 on this kernel. The m orthonormal pairs from step 2.1 and this n−m dimensional kernel account for all n+m dimensions and hence for the full spectrum of X.

4.1F1F3step 1.1step 3.1algebra∎

If C is the Cholesky factor in the symmetric-preconditioning definition, then Pγ=CCT. Let O=Pγ−1/2C; step 1.1 gives OOT=I, so O is orthogonal and C−1KC−T=OT(Pγ−1/2KPγ−1/2)O. Therefore the published Cholesky-symmetric preconditioning has the same spectrum as X. Since λ− decreases and λ+ increases on s>0, the eigenvalue intervals follow from step 1.1.

Depends on

Used by

Dependency tree · two levels

22 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources