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TheoremStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedjudge pass (gpt-6.1-sol)audited 2026-10-08
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Nondegeneracy of the residue pairing

Statement

Assume the Axiom of Choice (The Axiom of Choice). Let X be a compact Riemann surface, D a divisor, and E=OX(D). Put F:=K⊗E∗, where K=Λ1,0T∗X is the canonical bundle (The residue pairing for line-bundle cohomology); Choose a compatible Riemannian metric g on X and a Hermitian metric h on E, which exist under full AC (Hermitian metric and L2 pairing on a compact Riemann surface), and equip F with the tensor metric induced by g and the dual of h on E∗. Equivalently, the customary K−D twist means K⊗OX(−D)≅K⊗E∗ (The holomorphic line bundle associated to a divisor). Let BD:H1(X,OX(D))×H0(X,F)⟶C be the residue pairing of The residue pairing for line-bundle cohomology. Then BD is perfect:

  1. For every nonzero ξ∈H1(X,OX(D)), there is ω∈H0(X,F) such that BD(ξ,ω)≠0.
  2. For every nonzero ω∈H0(X,F), there is ξ∈H1(X,OX(D)) such that BD(ξ,ω)≠0.

Consequently the induced maps H1(X,OX(D))⟶H0(X,F)∗,H0(X,F)⟶H1(X,OX(D))∗ are complex-linear isomorphisms between finite-dimensional vector spaces (Finite-dimensionality of the cohomology of a divisor on a compact Riemann surface, Dolbeault cohomology of a compact riemann surface is finite dimensional).

Facts & Assumptions

Given: Full AC, a compact Riemann surface X, a divisor D, E=OX(D), compatible supplied metrics on X and E, the induced metrics on E∗ and F=K⊗E∗, and the intrinsic residue pairing of the preceding item.

[F1]

The intrinsic residue pairing is well defined and complex-bilinear, with BD(ξ,ω)=(2πi)−1∫Xθ∧ω for a smooth Dolbeault representative θ of ξ (The residue pairing for line-bundle cohomology).

[F2]

The canonical global comparison identifies H1(X,OX(D)) with the smooth Dolbeault quotient H0,1(X,E), naturally in the bundle and without a finite-cover hypothesis (Cech--Dolbeault comparison for holomorphic line bundles on a compact Riemann surface).

[F3]

The space H1(X,OX(D)) is finite-dimensional (Finite-dimensionality of the cohomology of a divisor on a compact Riemann surface).

[F4]

The divisor construction gives E∗≅OX(−D), so F=K⊗E∗ is the canonical twist denoted by K−D (The holomorphic line bundle associated to a divisor).

[F5]

The supplied metrics define the conjugate-linear bundle map #=⋆E and the positive identity u∧#u=∣u∣2 dVg (Hermitian metric and L2 pairing on a compact Riemann surface).

[F6]

The maximal Dolbeault operator defines the Hilbert harmonic space H0,1(X,E)=ker⁡Dˉ∗ and the Dolbeault Laplacian, with their stated domains (The maximal Dolbeault operator and its Hilbert adjoint on a compact Riemann surface).

[F7]

For the supplied metrics, # is a conjugate-linear isomorphism from H0,1(X,E) onto H0(X,F) for F=K⊗E∗, and u∧#u=∣u∣2 dVg (Harmonic star duality for line bundle valued dolbeault cohomology).

[F8]

The Dolbeault group H0,1(X,E) is finite-dimensional and every class has a unique smooth harmonic representative. Together with [F7], this also makes H0(X,F) finite-dimensional (Dolbeault cohomology of a compact riemann surface is finite dimensional).

[F9]

The scalar Hodge star on an oriented Riemannian manifold is characterized by α∧∗β=⟨α,β⟩gvol⁡g (Riemannian hodge star).

[F10]

Full AC is assumed by the sheaf-cohomology, finiteness, and Hodge inputs. No further choice is made in the pairing or the kernel arguments (The Axiom of Choice).

Proof

Transfer the pairing to the smooth Dolbeault model. The Hodge-star map identifies harmonic representatives with the dual holomorphic space; its positive norm identity proves both nondegeneracy directions.

1.1F2F3F4F6F7F8F10given

Put V:=H0,1(X,E) and W:=H0(X,F). By [F10], the cohomology and Hodge inputs below inherit the stated full Axiom of Choice. By [F2], the comparison isomorphism identifies H1(X,OX(D)) with V. The finite-dimensionality of H1(X,OX(D)) follows from [F3], while [F8] gives a unique harmonic representative in H0,1(X,E) for each class; [F7] carries that finite-dimensional harmonic space onto W.

2.1F1F5F6F7F8F9step 1.1algebra

Let 0≠ξ∈H1(X,OX(D)), and let 0≠u∈H0,1(X,E) be its harmonic representative under [F8]. By [F7], ω:=#u lies in W. The Hodge identity [F5, F7, F9] gives ∫Xu∧ω=∫X∣u∣2 dVg=∥u∥L22>0. Using u as the Dolbeault representative in [F1], BD(ξ,ω)=(2πi)−1∥u∥L22≠0. Thus the induced map H1(X,OX(D))→W∗ is injective.

2.2F1F2F5F6F7F8F9step 1.1algebra

Let 0≠ω∈W. By the isomorphism in [F7], there is a unique harmonic 0≠u∈H0,1(X,E) with #u=ω. Let ξ be its class under the inverse comparison [F2]. Then [F1] and the same positive norm identity give BD(ξ,ω)=(2πi)−1∥u∥L22≠0. Thus the induced map W→H1(X,OX(D))∗ is injective.

3.1F1F3F6F7F8step 2.1step 2.2algebra∎

The conjugate-linear isomorphism in [F7] and the harmonic-representative identification in [F8] give dim⁡CV=dim⁡CW. Both are finite-dimensional by [F3, F7, F8]. The two induced maps are complex-linear because BD is bilinear by [F1]; steps 2.1 and 2.2 show each is injective. An injective linear map between finite-dimensional spaces of equal dimension is surjective, so both maps are isomorphisms and BD is perfect.

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