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Non-degeneracy of the local intersection forms detects Soergel's conjecture one step higher

Facts & Assumptions

Given: Elements x,s with xs>x, the assumption S(y) for every y<xs, the module M=BxRBsR, the KL multiplication formula H‾xH‾s=H‾xs+∑y<xsμyH‾y with integer coefficients μy, and for every y<xs the finite-dimensional real space Ey=Hom⁡0(ByR,M) with its local intersection form (−,−)yx,s (The local intersection form on Hom(B_y, B_x B_s), Multiplication by a generator in the Kazhdan–Lusztig basis).

[F1]

Under S(y) for all y<xs, the comparison lemma gives the decomposition M=Bxs⊕⨁y<xsByR,ay with nonnegative integers ay and no grading shifts, with the top summand Bxs occurring exactly once; moreover ch⁡(Bz)=H‾z and h∇(Bz)=d(hΔ(Bz))=H‾z for every z<xs, while the characters of BxBs are computed multiplicatively as hΔ(M)=h∇(M)=H‾xH‾s (Indecomposable labels, characters and filtration ranks agree after real scalar extension, The type-A standard character is multiplicative).

[F2]

The graded rank of Hom⁡(ByR,M) is ⟨hΔ(ByR),h∇(M)⟩ for the standard pairing with ⟨Hu,Hv⟩=δuv on the normalized standard basis, and the trace-form values on the Kazhdan-Lusztig basis are (H‾u,H‾v)∈vZ[v] for u≠v and ∈1+vZ[v] for u=v; the Kazhdan-Lusztig coefficients satisfy pu,w∈vZ[v] for u<w (The type-A Soergel Hom formula, The Hecke trace form, its values on the Kazhdan-Lusztig basis, and the standard pairing).

[F3]

The local intersection form on Ey is symmetric and bilinear, and it is non-degenerate if and only if the degree-zero composition pairing Ey×Hom⁡0(M,ByR)→End⁡0(ByR)=R is a perfect pairing; the adjoint identification between the two Hom spaces preserves the rank (The local intersection form on Hom(B_y, B_x B_s)).

[F4]

Non-degeneracy of a symmetric bilinear form on a finite-dimensional real space is equivalent to the absence of a radical, i.e. to the form having maximal rank dim⁡Ey (Primitive subspaces, hard Lefschetz and the Hodge-Riemann signs: the dictionary of hypotheses S, hL and HR, Invariant forms on an indecomposable Soergel bimodule are unique up to scalar, non-degenerate, and agree with the restricted Bott-Samelson form).

Statement

Fix x,s with xs>x and assume S(y) for every y<xs. Put M=BxRBsR and write the Kazhdan-Lusztig multiplication formula H‾xH‾s=H‾xs+∑y<xsμyH‾y with integer constants μy. For each y<xs let Ey=Hom⁡0(ByR,M) carry the local intersection form of The local intersection form on Hom(B_y, B_x B_s). Then:

(1) dim⁡REy=μy, while the full graded Hom module has graded rank ⟨H‾y,H‾xH‾s⟩, generally not μy;

(2) the following are equivalent: S(xs); non-degeneracy of every local intersection form on Ey, y<xs; perfection of every degree-zero composition pairing Ey×Hom⁡0(M,ByR)→End⁡0(ByR)=R; and equality of the actual multiplicity ay of ByR in M with μy for every y<xs.

The unconditional top summand is Bxs with multiplicity one, and under S(<xs) all remaining summands are unshifted ByR. No positivity of Kazhdan-Lusztig polynomials or conjecture at xs is assumed.

Proof

technique · direct; constant-term Hom formula, character comparison and the multiplicity pairing
1.1givenF1F2

The dimension of Ey. By [F1] and [F2] the graded rank of Hom⁡(ByR,M) equals ⟨hΔ(ByR),h∇(M)⟩=⟨H‾y,H‾xH‾s⟩. Expanding H‾xH‾s=H‾xs+∑z<xsμzH‾z in the Kazhdan-Lusztig basis and using the trace values of [F2], this rank equals ∑zμz(H‾y,H‾z) up to the top term, whose contribution is δy,xs=0 because y<xs; each (H‾y,H‾z) lies in vZ[v] for z≠y and in 1+vZ[v] for z=y. Hence the constant term of the graded rank is μy, and since the graded rank lies in Z[v] with nonnegative v-powers, the degree-zero dimension is exactly the constant term: dim⁡REy=μy. This is the first assertion of (1); the full graded rank is the polynomial displayed and has higher-degree terms in general, so it is not in general equal to the integer μy.

2.1step 1.1F1F3

The top summand and the composition pairing. By [F1], M=Bxs⊕⨁y<xsByR,ay with the top summand of multiplicity one. For y<xs, consider a composite ByR→M→ByR factoring through a summand other than a copy of ByR; it cannot be a nonzero scalar multiple of the identity, because rescaling such a composite would exhibit a retraction splitting ByR off that other summand, contradicting the uniqueness of the indecomposable label. Hence only the ay copies of ByR contribute to the scalar-coordinate pairing, and the pairing matrix is the standard evaluation pairing of rank ay; by the adjoint identification of [F3] the local intersection form has the same rank.

3.1step 2.1F3F4

Non-degeneracy and the multiplicity equalities. By step 2.1 the local form on Ey is non-degenerate if and only if its rank equals dim⁡Ey, i.e. ay=μy; by [F4] this is equivalent to non-degeneracy in the sense of trivial radical. Therefore non-degeneracy of every local form for all y<xs is equivalent to the system of equalities ay=μy for all y<xs, and the same rank comparison identifies this with perfection of the composition pairings.

4.1step 1.1step 3.1F1∎

The character equivalence and conclusion. By additivity of the character and ch⁡(Bz)=H‾z for z<xs, the character of Bxs is ch⁡(M)−∑y<xsayH‾y=H‾xs+∑y<xs(μy−ay)H‾y. Since the Kazhdan-Lusztig basis is a basis of the Hecke algebra, ch⁡(Bxs)=H‾xs, i.e. S(xs), holds if and only if μy=ay for every y<xs. Combining with step 3.1 gives the equivalence of all four conditions in (2).

Remarks

  • The constant-term computation is the only place where the actual Hom dimension enters; the full graded rank is deliberately kept as a polynomial, since it is generally not the integer μy.
  • The equivalence proved here is Soergel's omnibus lemma in the form needed for the simultaneous induction; no positivity of Kazhdan-Lusztig polynomials is used, and the argument is finite and choice-free.

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