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Every nonzero fractional ideal of a Dedekind domain is invertible
Statement
Assume the Axiom of Choice. Every nonzero fractional ideal of a Dedekind domain is invertible.
Facts & Assumptions
Given: A Dedekind domain and a nonzero fractional ideal of .
A Dedekind domain is a Noetherian integrally closed domain of dimension (Dedekind domains).
A nonzero-prime localisation of a Dedekind domain is a DVR (Localizing a Dedekind domain at a nonzero prime gives a DVR).
Every nonzero ideal of a DVR is principal (Ideals in a DVR are powers of the maximal ideal).
A nonzero finitely generated fractional ideal is invertible exactly when all maximal localisations are principal (Equivalent characterizations of invertible fractional ideals).
Proof
Choose with . Then is a nonzero integral ideal of , so [F1] makes it finitely generated; hence the fractional ideal is finitely generated as well. Let be a maximal ideal. If , then , so is principal. If , then is a nonzero prime, [L1] makes a DVR, and [L2] makes the integral ideal principal. Hence is principal in either case. Thus is finitely generated and every maximal localisation of is principal.
Applying [L3] to step 1.1 shows that is invertible.
Depends on
Used by
- Prime-ideal valuations on fractional ideals Definition
Dependency tree · two levels
21 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.
Sources
- J. P. May, Notes on Dedekind Rings (standard reference, not scraped)
- J. S. Milne, A Primer of Commutative Algebra, §20 (standard reference, not scraped)
- Mircea Mustata, Introduction to Commutative Algebra, §8.5 (standard reference, not scraped)