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Eigenstructure of the admissible ideal-gas Euler system

Statement

For U=(ρ,m,E)∈Gγ, put u=m/ρ, H=(E+p)/ρ, and c=γp/ρ. The flux Jacobian has the three simple real eigenvalues and right eigenvectors λ−=u−c,r−=(1,u−c,H−uc)T, λ0=u,r0=(1,u,u2/2)T, λ+=u+c,r+=(1,u+c,H+uc)T. The middle field is linearly degenerate; the acoustic fields are genuinely nonlinear, with Dλ−r−=−(γ+1)c/(2ρ) and Dλ+r+=(γ+1)c/(2ρ).

Facts & Assumptions

Given: γ>1 and an admissible ideal-gas Euler state.

[F1]

Admissible states and pressure for one-dimensional ideal-gas Euler: p=(γ−1)(E−m2/(2ρ)), F=(m,m2/ρ+p,u(E+p)), and c2=γp/ρ.

[F2]

Strictly hyperbolic conservation systems and characteristic families: eigenpairs are right eigenvectors of DF; genuine nonlinearity and linear degeneracy are tested by Dλiri.

Proof

1.1givenF1algebra

Write U=(ρ,ρu,E) and use [F1] to obtain H=u2/2+c2/(γ−1). Differentiating the flux components with respect to (ρ,m,E) gives DF(U)=(010(γ−3)u2/2(3−γ)uγ−1u((γ−1)u2/2−H)H−(γ−1)u2γu).

2.1step 1.1algebra

Multiplying DF by r0 gives (u,u2,u3/2)T=ur0. For r±, the first row gives u±c; the second gives (3−γ)u2/2+(γ−1)H±2uc=u2+c2±2uc=(u±c)2; and the third gives γuH−(γ−1)u3/2±c(H+u2)=u(H+c2)±c(H+u2)=(u±c)(H±uc). Each row therefore equals the matching component of (u±c)r±, using H=u2/2+c2/(γ−1). Since c>0, the eigenvalues are distinct and strictly ordered.

2.2step 1.1F1F2algebra

For a state increment (dρ,dm,dE), differentiating the definitions gives du=(dm−u dρ)/ρ and dp=(γ−1)(dE−u dm+u2dρ/2). Along r±, these yield du=±c/ρ and dp=c2; hence dc=12c(dp/p−dρ/ρ)=(γ−1)c/(2ρ). Along r0 they give du=dp=0 and dc=−c/(2ρ); in particular Dλ0r0=du=0. Therefore the stated directional derivatives of u−c,u,u+c follow.

3.1step 2.2F2algebra∎

Because c,ρ,γ are positive, the acoustic directional derivatives are nonzero with the displayed signs, while the middle one is zero. This proves genuine nonlinearity of the two acoustic fields and linear degeneracy of the contact field.

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