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The periodic PIC Poisson algorithm returns the unique gauged solution

Statement

For every real zero-mean source s on the grid of Periodic uniform PIC grid and inner product, Fourier diagonal solver for the periodic centered-difference Poisson equation terminates and returns the unique ϕ satisfying Ahϕ=s and ϕˉ=0. Its incompatible-source branch is taken exactly when the equation has no solution.

Facts & Assumptions

Given: A real grid source and the exact-arithmetic finite Fourier procedure.

[F1]

Periodic centered-difference Poisson solvability and zero-mean gauge: the Fourier characters diagonalize Ah, λh(k)>0 for k≠0, and a zero-mean source has a unique zero-mean solution.

[F2]

Fourier diagonal solver for the periodic centered-difference Poisson equation: the procedure checks sˉ, sets ϕ^0=0, divides each other coefficient by λh(k), and applies the inverse finite Fourier transform.

Proof

1.1F1F2algebra

The source and grid contain finitely many real numbers, so computing its mean and finite Fourier transform terminates. If sˉ≠0, then the constant Fourier coefficient of s is nonzero while Ah annihilates constants and has zero constant coefficient on every output, so Ahϕ=s is impossible.

2.1F1F2step 1.1algebra

If sˉ=0, its zero Fourier coefficient is zero. By [F1], every other eigenvalue is positive, so all divisions in [F2] are defined. For real input, s^−k=s^k‾ and λh(−k)=λh(k); therefore the returned coefficients have the same conjugate symmetry, and pairing the k and −k terms in the inverse transform shows every ϕj is real. For every nonzero mode, the returned coefficient satisfies λh(k)ϕ^k=s^k, and the zero mode satisfies 0=s^0. Inverse Fourier transformation therefore gives Ahϕ=s and ϕ^0=0 gives ϕˉ=0.

3.1F1step 2.1∎

The coefficient list is finite, hence inverse transformation terminates. Uniqueness of the returned gauged solution follows from [F1].

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