Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedprecheck passaudited 2026-10-08
How statement and proof provenance work

The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Projective embedding of a compact Riemann surface

Statement

Assume full AC (The Axiom of Choice). Let X be a compact Riemann surface of genus g, let D be any divisor with deg⁡D≥2g+1, and put E=OX(D) and N=ℓ(D)−1. Then:

  1. ℓ(D)=deg⁡D+1−g≥g+2, and the complete linear system of holomorphic sections H0(X,E) is base-point-free. For every p∈X, ℓ(D−[p])=ℓ(D)−1.
  2. For distinct p,q∈X, ℓ(D−[p]−[q])=ℓ(D)−2. There are sections s,t with s(p)=0, s(q)≠0, t(q)=0, t(p)≠0; hence the complete-linear-system map φD:X→PN(C) is injective.
  3. For every p∈X, ℓ(D−2[p])=ℓ(D)−2. There is a section with a zero of order exactly one at p, and φD is a holomorphic immersion.
  4. The map φD is a holomorphic embedding, with its basis-independent intrinsic target P(H0(X,E)∗) and the usual projective-coordinate change for a different basis (The map defined by a base-point-free linear system).

Values and vanishing orders here are those of holomorphic bundle sections. If h∈L(D) represents a section, its local holomorphic coefficient is hfi in a divisor-bundle frame with sD=fiei; the meromorphic function h itself may have an allowed pole at p.

Facts & Assumptions

Given: Full AC, compact X of genus g, and deg⁡D≥2g+1.

[F1]

Full AC is the premise inherited from the cohomology and duality suppliers (The Axiom of Choice).

[F2]

Riemann–Roch gives ℓ(A)−i(A)=deg⁡A+1−g, ℓ(0)=1, i(0)=g, and existence of a canonical divisor K; Serre duality gives i(A)=ℓ(K−A) (The Riemann-Roch theorem on a compact Riemann surface, Serre duality on a compact Riemann surface).

[F3]

Negative-degree divisors have zero L-space, and principal divisors have degree zero (Divisors, principal divisors and canonical divisors on a Riemann surface).

[F4]

H0(X,OX(A))≅L(A) via h↦hsA, and sA=fiei with (sA)=A. A nonzero section has zero divisor (h)+A (The holomorphic line bundle associated to a divisor, Divisors, principal divisors and canonical divisors on a Riemann surface).

[F5]

Holomorphic sections have holomorphic coefficients in local holomorphic frames, and a nonzero coefficient factors by its finite zero order (Holomorphic line bundles and meromorphic sections on a Riemann surface).

[F6]

A base-point-free finite-dimensional space of sections defines a canonical holomorphic map to the projectivization of its dual; in a local frame its coordinates are the section coefficients, and a basis change is a projective linear change (The map defined by a base-point-free linear system).

[F7]

Projective space has holomorphic affine charts and is a Hausdorff smooth manifold; holomorphic functions are smooth (Complex projective space and its holomorphic charts, Holomorphic functions are real analytic and smooth in their two real coordinates).

[F8]

A smooth immersion has injective differential, and an embedding is an immersion and a homeomorphism onto its image. An injective smooth immersion from a compact manifold to a Hausdorff manifold is an embedding (Immersions and embeddings for manifolds with boundary, An injective immersion from a compact manifold is an embedding).

Proof

1.1F1F2F3givenalgebra

Choose a canonical divisor K by [F2]. Duality at 0 gives ℓ(K)=g and at K gives i(K)=ℓ(0)=1, so Riemann–Roch at K yields deg⁡K=2g−2. For A=D,D−[p],D−[p]−[q] or D−2[p], the degree is at least 2g−1>2g−2. Thus [F3] gives ℓ(K−A)=0, and [F2] gives ℓ(A)=deg⁡A+1−g. This proves every displayed dimension drop and ℓ(D)≥g+2.

2.1F4F5F6step 1.1choosealgebra

By [F4], sections vanishing at p correspond exactly to L(D−[p]): in a local frame their zero order is ord⁡p(h)+D(p). Step 1.1 makes this a proper codimension-one subspace, so some section is nonzero at each p. Hence H0(X,E) is base-point-free and [F6] supplies φD. At distinct p,q, the sections vanishing at both form L(D−[p]−[q]), a proper subspace of L(D−[p]) by step 1.1; choose a section vanishing at p but not at q, and symmetrically one vanishing at q but not at p. If φD(p)=φD(q), their nonzero evaluation functionals would be proportional and have the same kernel, contrary to those sections. Thus φD is injective.

3.1F4F5F6F7F8step 1.1step 2.1choosealgebra

Fix p. By step 1.1 choose a section s∈H0(E(−[p]))∖H0(E(−2[p])), and by step 2.1 choose t∈H0(E) with t(p)≠0. In a local coordinate z centred at p and a holomorphic frame e, write s=a(z)e, t=b(z)e; [F4] and [F5] give a(z)=zu(z) with u(0)≠0 and b(0)≠0. Since s,t are independent, extend them to a basis of H0(E). In the target affine chart corresponding to t, a coordinate of φD is a/b, whose derivative at p is u(0)/b(0)≠0. Basis changes are holomorphic projective automorphisms by [F6], so the differential is nonzero for every basis. It is a nonzero complex-linear map from a one-dimensional complex tangent space, hence injective as a real-linear map. Thus [F7] and [F8] make φD a smooth and holomorphic immersion. This argument uses the regular coefficients hfi, even when the representing meromorphic functions have poles.

4.1F6F7F8step 2.1step 3.1∎

The map is injective by step 2.1 and immersive by step 3.1; X is compact and projective space is Hausdorff by [F7]. Hence [F8] makes it a homeomorphism onto its image and a smooth embedding. Its local expressions are holomorphic by [F6], so it is the asserted holomorphic embedding. The intrinsic target and basis covariance are those in [F6].

Depends on

Used by

Nothing in the library uses this result yet.

Dependency tree · two levels

74 results within two dependency steps of this one, each drawn at its shortest distance from it. An arrow runs from a result to what uses it, so the chart reads left to right and ends at this result, which carries a heavier outline. Every node is a link to that result. Click elsewhere on the chart to enlarge it.

Sources