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Every compact Riemann surface admits a nonconstant meromorphic function

Statement

Assume the full Axiom of Choice (The Axiom of Choice). Let X be a compact Riemann surface of topological genus g and let p∈X. Put D0:=2g[p] and FD0:=KX⊗OX(−D0), where KX:=Λ1,0T∗X is the canonical line bundle (Divisors, principal divisors and canonical divisors on a Riemann surface, Serre duality on a compact Riemann surface). Then:

  1. ℓ(D0)=g+1, and the intrinsic Riemann–Roch correction is ℓ(D0)−h0(X,FD0)=g+1. There exists a nonzero meromorphic differential η on X. For every such differential, put Kη:=(η); then deg⁡Kη=2g−2, ℓ(Kη−D0)=0, and the correction identity is ℓ(D0)−ℓ(Kη−D0)=g+1 (Meromorphic differentials, orders and residues, The Riemann-Roch theorem on a compact Riemann surface). If g≥1, a nonzero holomorphic differential exists as well.

  2. There is a nonconstant meromorphic function whose only possible pole is p, of order at most 2g if g≥1 and at most 1 if g=0. Viewed as a holomorphic map X→C^, it is proper and has degree at most max⁡{1,2g} (Holomorphic maps and meromorphic functions on Riemann surfaces, Degree of a proper holomorphic map of Riemann surfaces).

Facts & Assumptions

Given: Full AC, a compact Riemann surface X of topological genus g, and a point p∈X.

[F1]

Full AC is assumed by the cohomology, duality, and Riemann–Roch suppliers (The Axiom of Choice).

[F2]

For a divisor D, L(D) consists of 0 and the meromorphic functions satisfying (f)+D≥0; at a point outside the support of D, every element of L(D) is holomorphic (Divisors, principal divisors and canonical divisors on a Riemann surface).

[F3]

For topological genus g, ℓ(0)=1 and i(0)=h1(X,OX)=g (The Euler characteristic of the structure sheaf is one minus the genus).

[F4]

Serre duality identifies i(0)=h1(X,OX) with h0(X,KX) (Serre duality on a compact Riemann surface).

[F5]

For every divisor D, ℓ(D) and i(D) are finite and the intrinsic formula is ℓ(D)−h0(X,KX⊗OX(−D))=deg⁡D+1−g (The Riemann-Roch theorem on a compact Riemann surface).

[F11]

A nonzero meromorphic differential exists, and for every such η with Kη=(η), i(D)=ℓ(Kη−D) (The Riemann-Roch theorem on a compact Riemann surface).

[F6]

A nonzero holomorphic section of KX=Λ1,0T∗X is a nonzero holomorphic, hence meromorphic, differential (Meromorphic differentials, orders and residues).

[F7]

A meromorphic function on X is a holomorphic map X→C^ other than the constant map at ∞ (Holomorphic maps and meromorphic functions on Riemann surfaces).

[F8]

A proper nonconstant holomorphic map between connected Riemann surfaces has positive degree d=∑x∈f−1(y)ex(f), independent of y (Degree of a proper holomorphic map of Riemann surfaces).

[F9]

On compact X, a nonconstant meromorphic function is proper as a map to C^ (Divisors, principal divisors and canonical divisors on a Riemann surface).

[F10]

If X is compact and deg⁡D<0, then L(D)=0 (Divisors, principal divisors and canonical divisors on a Riemann surface).

[F12]

At a pole q of a meromorphic function f:X→C^, its divisor order is −eq(f) (Divisors, principal divisors and canonical divisors on a Riemann surface).

[F13]
[F14]

All canonical divisors are linearly equivalent (Divisors, principal divisors and canonical divisors on a Riemann surface).

Proof

Riemann–Roch supplies a canonical divisor and computes its degree at every genus. The nonconstant function is obtained from 2g[p] in positive genus and from [p] in genus zero.

1.1F1F3F4F5F6F11F13F14givenchoosealgebra

By [F11], choose a nonzero meromorphic differential η and put Kη=(η). By [F11] at D=0 and [F3], ℓ(Kη)=i(0)=g. At D=Kη, [F11] gives i(Kη)=ℓ(0)=1, and [F5] gives ℓ(Kη)−i(Kη)=deg⁡Kη+1−g. Thus g−1=deg⁡Kη+1−g, so deg⁡Kη=2g−2 for every genus. By [F13] and [F14], every other canonical divisor has this same degree. If g≥1, [F3] and [F4] give h0(X,KX)=g>0, so [F6] also gives a nonzero holomorphic differential.

2.1F5F10F11step 1.1algebra

By [F5], the intrinsic correction at D0 is ℓ(D0)−h0(X,FD0)=2g+1−g=g+1, and [F11] identifies h0(X,FD0)=i(D0)=ℓ(Kη−D0). By step 1.1, deg⁡(Kη−D0)=(2g−2)−2g=−2 at every genus, so [F10] gives ℓ(Kη−D0)=0 and hence ℓ(D0)=g+1. In particular, when g=0, D0=0 and ℓ(D0)=1; no nonconstant function is inferred from this space.

3.1F1F2F3F5step 2.1algebra

If g≥1, then ℓ(D0)=g+1≥2 by step 2.1. The constants form a one-dimensional subspace of L(D0) by [F3], so choose a nonconstant f∈L(D0). If g=0, [F5] applied to [p] gives ℓ([p])−i([p])=2, hence ℓ([p])≥2; the constants again form a one-dimensional subspace, so choose a nonconstant f∈L([p]). By [F2], membership in these spaces means that all poles are confined to p, with order at most 2g in the first case and at most 1 in the second.

4.1F7F8F9F12step 3.1∎

By [F7], f is a nonconstant holomorphic map to C^. It is proper by [F9], so [F8] computes its degree by the weighted fibre over ∞. There are no poles away from p, and at p the local multiplicity equals the pole order by [F12]. Thus the degree is at most 2g when g≥1 and at most 1 when g=0; in both cases it is at most max⁡{1,2g}.

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