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Binary search converts certified SDP thresholds to additive optimization

Statement

For the normalized nonempty SDP and bounded attained dual optimum of Matrix-weights regret implies SDP threshold feasibility, let 0<ε<2R, supply a rational ε0 with ε/2<ε0≤ε, set e=ε0/8, and supply that lemma's finite threshold oracle. On its good event LOWER supplies a feasible dual of objective at most α+e, and HIGHER implies α<OPT. Initialize lo=−R,hi=R, obtain a LOWER vector at threshold R+e, and store it. For at most L=⌈log⁡2(16R/ε0)⌉+2 midpoint calls, stop when hi−lo≤ε0/2; on LOWER store its vector and put hi=min⁡(hi,α+e), and on HIGHER put lo=max⁡(lo,α−e). Then the stored vector is dual feasible and has objective at most OPT+ε. There are O(1+log⁡(R/ε)) threshold calls. Per-call conditional bad probability at most δ/(L+1) gives total failure at most δ, even for adaptive inputs.

An uncertain result with no proved oracle guarantee returns explicit FAIL. No tolerance refinement is required on a good execution. For ε≥2R return e1 directly. If R=0 and the primal is nonempty, the same vector has objective zero and is optimal. In dimension zero return the zero dual vector. These branches precede every division by R.

Facts & Assumptions

Given: The normalized SDP promises, finite threshold oracle and the stated conditional budgets.

[F1]

Normalized Hermitian inequality SDPs have equal primal and dual values gives primal/dual equality and OPT∈[−R,R] when R>0.

[F2]

Matrix-weights regret implies SDP threshold feasibility gives the good-event threshold alternatives and feasible sparse dual certificate.

[F3]

Finite semidefinite primal-dual pair fixes dual feasibility and the identity trace constraint.

Proof

1.1givenF1F2algebra

By [F1], the first threshold R+e exceeds the optimum, so [F2] cannot return HIGHER on its good event. It supplies a stored feasible vector with objective B≤R+2e. Thus the invariant lo≤OPT≤hi and B≤hi+2e holds initially. At a LOWER midpoint, OPT≤Bnew≤α+e; replacing hi by its minimum with α+e keeps the optimum bracketed. If that endpoint changes, Bnew≤hi; if clamping leaves it unchanged, Bnew≤α+e≤hi+e. Thus storing the new vector still gives B≤hi+2e. At HIGHER, α<OPT, so the lower-endpoint update preserves the bracket and changes no stored certificate.

2.1givenF2step 1.1algebra

With W=hi−lo, either update gives Wnew≤W/2+e. Induction gives Wj≤2e+2R2−j. At j=L this is at most ε0/4+ε0/32<ε0/2. While the stopping test fails, W>4e, so Wnew≤W/2+e<3W/4<W; clamping cannot prevent contraction. Hence every good execution reaches the stopping width within the fixed cap without refinement. At exit the stored vector remains feasible and B−OPT≤hi−lo+2e≤3ε0/4<ε0≤ε. Since ε0>ε/2, its call cap is O(1+log⁡(R/ε)). This includes the case of only HIGHER midpoint responses, using the initial certificate.

3.1givenstep 1.1step 2.1algebra

Condition on each reached history before the first bad complete threshold call. Until then steps 1.1–2.1 show there are at most L+1 calls and no refinements. Summing their conditional probabilities gives first-bad-call probability at most (L+1)δ/(L+1)=δ. Additional operations on an already bad path do not add a second probability for that same bad event. This is valid without independence. A declared unresolved numerical failure is not interpreted as a threshold exclusion; the final high-probability conclusion requires the supplied complete oracle's good-event contract.

4.1givenF1F3algebra∎

Since ∥C∥≤1, I−C⪰0 and e1 is dual feasible with objective R. For ε≥2R, [F1] gives R≤OPT+ε. For R=0, the identity constraint and nonnegative eigenvalues force every feasible primal X to be zero; weak duality and the feasible zero-objective vector e1 give optimum zero directly. For dimension zero, primal nonemptiness implies bj≥0, so the zero vector is feasible and optimal. These branches establish the remaining cases without using the positive-R formulas.

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