Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedjudge pass (gpt-6-luna)
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QC24 Discrete Alphabet Approximate Preparation Lower Bound

Statement

Fix real numbers 0<δ<1/4 and 0≤ε<δ. Let integers n≥2, A≥1, k≥1, and W≥n be fixed, with D=2n, gate-alphabet size A, and maximum arity k. For an integer gate budget g≥0, every circuit starts on ∣0n⟩∣0W−n⟩ and must return the workspace exactly to zero, with its data output within projective chord distance ε of the target ray. If a circuit family prepares every D-dimensional pure-state ray and each circuit in the family has at most g gates in this model, then g=Ω(D/log⁡W) as n→∞, with constants depending on A,k,δ,ε. In particular, if W=poly⁡(n), then g=Ω(2n/log⁡n).

Facts & Assumptions

Given: The fixed finite-alphabet width model with exact clean-workspace output, fixed integers A≥1, k≥1, and fixed δ,ε in the Statement, and the ray-packing and circuit-count bounds below.

[F1]

The page contains at least exp⁡(cδD) rays pairwise separated by at least 2δ in dch (QC24 Signed Ray Packing Code).

[F2]

At width W, a length-j circuit has at most (CkAWk)j descriptions, with Ck=k+1 (QC24 Finite Width Topology Count).

[F3]

dch([u],[v])=2−2∣⟨u,v⟩root∣ and the phase-minimum is attained (Projective Chord Distance Formula).

[F4]

The Euclidean norm induced by the root inner product satisfies the triangle inequality (The inner-product norm is definite, homogeneous, and satisfies the triangle inequality).

Proof

Given: As in Facts & Assumptions.

1.1F1F3F4givenalgebracontradiction

A single output ray cannot be within ε of two distinct packed rays. Indeed, if dch([u],[q])≤ε and dch([v],[q])≤ε, [F3] gives unit phases λ,μ with ∥u−λq∥2≤ε and ∥v−μq∥2≤ε; then [F4] gives ∥u−(λ/μ)v∥2≤2ε<2δ, contradicting [F1]. Thus each circuit covers at most one packed ray.

2.1F1F2step 1.1algebra

Put B=CkAWk≥2. By [F2], the number of descriptions of length at most g is ∑j=0gBj≤Bg+1. If these circuits approximate all packed rays, step 1.1 implies exp⁡(cδD)≤Bg+1, so g≥cδD/log⁡B−1.

3.1givenF1step 2.1algebracases∎

Since A,k are fixed and W≥2, there is a constant K>0 with log⁡B=log⁡(CkA)+klog⁡W≤Klog⁡W. Put X=cδD/(Klog⁡W). Step 2.1 gives g+1≥X. If X≥2, then g≥X−1≥X/2. If X<2, a family with g=0 has only the single zero-gate output ray, whereas the packing in [F1] contains at least two rays for D≥4; hence g≥1>X/2. Thus g≥X/2=Ω(D/log⁡W). If W=poly⁡(n), then log⁡W=O(log⁡n) and also W≥n, so log⁡W=Θ(log⁡n), giving Ω(2n/log⁡n).

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