Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedjudge pass (gpt-6-luna)
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Fuchs Van De Graaf

Statement

For density operators ρ,σ on a nonzero finite-dimensional complex Hilbert space, 1−F(ρ,σ)≤D(ρ,σ)≤1−F(ρ,σ)2, where F is root fidelity and D(ρ,σ)=12∥ρ−σ∥1.

Facts & Assumptions

Given: Density operators ρ,σ on a nonzero finite-dimensional H.

[L1]

Some finite rank-one PVM has classical overlap ∑apaqa=F(ρ,σ), and every such measurement has total variation at most D (Fidelity classical measurement minimum, Trace Distance, Measurement Variation At Most Trace Distance).

[L2]

Taking the fixed auxiliary space R=H, there are purifications with overlap F (Fidelity Purification Characterization); the QC06 theorem proves this as part of its every-R statement.

[L3]

For unit vectors x,y, D(∣x⟩⟨x∣,∣y⟩⟨y∣)=1−∣⟨x,y⟩∣2 (Pure state trace distance).

[L4]

Proof

1.1givenL1algebra

Let (Ea) be the rank-one PVM from [L1], with probabilities pa=tr⁡(ρEa) and qa=tr⁡(σEa). For nonnegative p,q, pq≥min⁡(p,q) because if p≤q then pq≥p2, and the other case is symmetric. Since ∑apa=∑aqa=1, 1−F=1−∑apaqa≤1−∑amin⁡(pa,qa)=12∑a∣pa−qa∣≤D(ρ,σ). The last inequality is [L1].

2.1givenL2L3L4∎

Choose purifications x,y attaining the overlap ∣⟨x,y⟩∣=F(ρ,σ) by [L2]. By [L3], their pure-state trace distance is 1−F(ρ,σ)2. Taking the partial trace over the auxiliary factor maps their rank-one projectors to ρ and σ; contractivity [L4] therefore gives D(ρ,σ)≤1−F(ρ,σ)2. This proves the upper bound.

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