Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-adaptedPipeline-generatedjudge pass (gpt-6-luna)
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  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
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Optimal Universal Pure State Cloning Bound

Statement

Assume the choice branch used by the normalized Haar moment theorem. For d≥1 and 1≤n≤m, the largest possible worst-case squared root fidelity of a channel from n identical d-dimensional input registers to m output registers is NnNm,Nr=(r+d−1d−1). For n=1,m=2 this value is 2/(d+1).

Facts & Assumptions

Given: d≥1, 1≤n≤m, and the choice-dependent symmetric-subspace/Haar results.

[L1]

Every such channel has worst-case squared fidelity at most Nn/Nm (Optimal Cloning Worst Case Upper Bound, The Axiom of Choice). The lemma is a draft and depends on the Haar-moment branch.

[L2]

The displayed measure-and-prepare correction channel is CPTP and has squared fidelity exactly Nn/Nm on every pure input (Optimal Cloner Attains Bound). Its supplier is a draft.

Proof

1.1givenL1L2algebra

The upper bound [L1] applies to every admissible channel. The explicit channel in [L2] belongs to this same class and attains the bound for every unit input, so its worst-case value is at least Nn/Nm. Combining the two inequalities shows that the supremum over channels is exactly Nn/Nm, and the construction attains it.

2.1givenstep 1.1algebra∎

For n=1,m=2, N1=(dd−1)=d and N2=(d+1d−1)=d(d+1)/2. Their ratio is 2/(d+1), including d=1, where it equals one and the one-dimensional state is cloned trivially.

Depends on

Used by

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Sources