Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-adaptedprecheck passaudited 2026-08-02
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Multiplication of additive cosets is well defined if and only if the additive subgroup is a two-sided ideal

Statement

Multiplication of additive cosets is well defined if and only if the additive subgroup is a two-sided ideal.

Let J≤(R,+). The rule (r+J)(s+J)=rs+J is independent of representatives exactly when J⊴R.

Facts & Assumptions

Given: A ring R and an additive subgroup J≤(R,+).

[L1]

The displayed rule is the proposed quotient multiplication (The quotient ring R/I with (r+I)(s+I)=rs+I).

[L2]

A two-sided ideal is an additive subgroup absorbing multiplication on both sides (Left, right and two-sided ideals).

[L4]

Coset equality is membership of a difference in the subgroup (x∈aH iff a−1x∈H, and aH=bH iff a−1b∈H).

[L5]

Additive cosets are available for an additive subgroup (The quotient group G/N and coset product (gN)(hN)=ghN).

Proof

technique · direct
1.1

If J is an ideal and r′=r+i, s′=s+j, then r′s′−rs=rj+is+ij∈J, so the product is well defined.

L1L2L3L4L5givenalgebra
2.1

Conversely, compare (r+J)(0+J) with (r+J)(j+J) and the reversed product; [L4] gives rj,jr∈J for all r,j.

step 1.1L1L2L3L4L5givenalgebra
3.1

Thus the rule is well defined exactly when J is a two-sided ideal.

step 2.1∎

Depends on

Used by

Cited to discharge well-definedness by The quotient ring R/I with (r+I)(s+I)=rs+I.

Dependency tree · two levels

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Sources