Alphabeta Math
TheoremStatement: Literature-sourcedProof: AI-adaptedSession-authored (Fable 5 assisted)precheck passjudge pass (deepseek-v4-pro + gpt-5.6-terra)audited 2026-08-16
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The first chip identifies the source of the statement or construction; the second identifies the source of its local proof or verification.

  • Literature-sourced: the exact statement appears in a cited source; only wording and notation differ.
  • AI-adapted: a semantically identical restatement of literature-sourced material, modulo indexing, notation, and boundary cases adopted by the library.
  • AI-generated: a genuinely novel statement formulated by AI, with no source for the claim itself.

These labels describe origin, not correctness: citations and verification chips remain separate evidence.

Universal property of the quotient vector space

Statement

Let f:VU be linear and let WV satisfy Wkerf. There is a unique linear map fˉ:V/WU such that fˉπ=f. It is given by fˉ(v+W)=f(v).

Facts & Assumptions

Given: A linear map f:VU and a subspace Wkerf.

[L1]

v+W=v+W exactly when vvW, the operations on V/W make it a vector space over F, and the canonical projection π:VV/W is a surjective linear map with kerπ=W (Coset equality, well-defined quotient operations, and the canonical projection with kernel W).

[L2]

For a linear map f, its kernel is kerf={v:f(v)=0} (Kernel and image of a linear map).

[L3]

The quotient operations are (v+W)+(u+W):=(v+u)+W and a(v+W):=(av)+W, and the canonical projection is π(v):=v+W (The quotient vector space V/W and its canonical projection).

Proof

technique · direct
1.1

Define fˉ(v+W):=f(v); if v+W=v+W, then vvWkerf by [L1], so f(v)f(v)=f(vv)=0 by [L2] and the linearity of f, giving f(v)=f(v), and fˉ is well defined; the operation formulas of [L3] then give fˉ(a(v+W)+b(u+W))=fˉ((av+bu)+W)=f(av+bu)=af(v)+bf(u), so fˉ is linear.

L1L2L3
2.1

The definition gives fˉ(π(v))=f(v), hence fˉπ=f; if g:V/WU also satisfies gπ=f, then every coset is π(v) and g(v+W)=f(v)=fˉ(v+W), so g=fˉ, including the cases W=V and V=0.

step 1.1L1

Depends on

Used by

Dependency tree · next 3 levels

Direct dependencies and their dependencies through the next three levels: 15 results over 10 levels. An arrow runs from a result to what uses it, and this result sits at the bottom with a heavier outline. Click the chart to enlarge it.

Sources