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Rademacher uniform generalization bounds
Statement
Assume the Axiom of Choice (AC). Let be a probability space, let , and let be a nonempty class of measurable functions . Take to be the coordinate sample with law . Put and . Assume the sample, independent-copy and sign suprema over and used in the displayed claims and the symmetrization argument are measurable. Let be independent uniform signs, and let
where the are independent uniform signs, and let . Each of the following four guarantees holds with probability at least over :
The four guarantees are separate probability statements. The choice axiom is used through the bounded-differences theorem.
Statement references
One-sided Rademacher complexity: fixes the one-sided empirical and expected complexities and their normalization.
One-sided Rademacher symmetrization bound: bounds the expected one-sided deviation by twice the expected complexity.
McDiarmid bounded-differences inequality: supplies bounded-differences concentration under AC.
The Axiom of Choice: AC is the stated set-theoretic axiom carried by the concentration theorem.
The natural logarithm as the inverse of the exponential function: defines as the inverse of the exponential on positive inputs.
Order, continuity, range, and the product, quotient, and reciprocal laws for the natural logarithm: gives the reciprocal law and monotonicity of .
Basic identities for a probability measure: gives finite subadditivity for the union bounds.
Mohri et al., Theorem 3.3 and complete proof, printed pp. 31–33: proves both one-sided bounds with the stated constants in the adopted normalization.
Bartlett and Mendelson, Theorems 5 and 8 with proofs, printed pp. 464–467 and 479–480: gives independent risk-bound proofs in its separate absolute/ convention.
Facts & Assumptions
Given: AC, IID observations with law , a nonempty measurable class of -valued functions, measurable suprema, and .
AC states that every family of nonempty sets has a choice function. It is invoked only through the McDiarmid supplier, whose theorem assumes AC and whose proof uses it in the conditional-expectation / martingale construction. The Axiom of Choice
For , ; is the sign-average one-sided supremum with normalization , and . One-sided Rademacher complexity
For an IID sample and measurable suprema, ; this expectation inequality is choice-free. One-sided Rademacher symmetrization bound
If a product-measurable integrable function of independent coordinates changes by at most when coordinate changes, AC gives the upper-tail bound ; applying it to gives the lower-tail version. McDiarmid bounded-differences inequality
For , is the unique real with . The natural logarithm as the inverse of the exponential function
is strictly increasing, , and for ; it is the inverse of the exponential on positive inputs. Order, continuity, range, and the product, quotient, and reciprocal laws for the natural logarithm
IID means the sample coordinates are mutually independent and have the common law . Identical distribution and IID families
A finite union of events has probability at most the sum of their probabilities. Basic identities for a probability measure
Proof
Given: The hypotheses in the Statement.
Put . Changing one coordinate changes each term in this supremum by at most , hence . By the Statement, is measurable, and it is bounded because . Since , [F5] and give ; [F4]–[F5] give . McDiarmid [F3] with gives with probability at least , and [F2] bounds its expectation by . This proves the first one-sided bound.
For each fixed sample, . The first term has mean zero and has the same uniform law as , so this equals ; taking expectations gives .
For each fixed sign vector, changing one observation changes every by at most , since takes values in ; the same bound holds for the supremum and then for its sign average . This statistic is bounded and measurable by the Statement. With as in step 1.1, [F3] applied to its negative gives with probability at least .
For , . Apply step 1.1 to and with failure probability each. By [F7] and step 1.2, both deviations are at most except on an event of probability at most . This proves the first two-sided bound.
Apply step 1.1 with failure probability and step 2.1 with failure probability . By [F7], both events hold with probability at least . Since , [F5] gives ; combining the two bounds gives . This is the second one-sided guarantee.
Apply step 3.1 to and with failure probability each. Their complexities agree by step 1.2, and their upper deviations are and , respectively. By [F7] the two bounds hold together with probability at least , giving the last two-sided bound with .
Depends on
- The Axiom of Choice
- Identical distribution and IID families
- The natural logarithm as the inverse of the exponential function
- Basic identities for a probability measure
- One-sided Rademacher complexity
- Order, continuity, range, and the product, quotient, and reciprocal laws for the natural logarithm
- McDiarmid bounded-differences inequality
- One-sided Rademacher symmetrization bound
Used by
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Sources
- Mehryar Mohri, Afshin Rostamizadeh, and Ameet Talwalkar, Foundations of Machine Learning, 2nd ed., Theorem 3.3 and proof (standard reference, not scraped)
- Peter L. Bartlett and Shahar Mendelson, Rademacher and Gaussian Complexities: Risk Bounds and Structural Results, JMLR 3 (2002), Theorems 5 and 8 with proofs (standard reference, not scraped)