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Robbins–Monro converges almost surely for a strongly monotone root

Statement

Assume the Axiom of Choice. Let h:Rd→Rd have a root x∗, so h(x∗)=0, and suppose that for some μ>0, ⟨h(x)−h(y),x−y⟩≥μ∥x−y∥22(x,y∈Rd). On a filtered probability space, let x0 be square-integrable and let xk,Gk follow Filtration-adapted stochastic-gradient oracles and Robbins–Monro updates. Assume each h(xk) is Fk-measurable, and suppose E[Gk∣Fk]=h(xk),E[∥Gk∥22∣Fk]≤M2 almost surely for a finite constant M. If the deterministic stepsizes satisfy αk>0, ∑kαk=∞, and ∑kαk2<∞, then xk→x∗ almost surely. Strong monotonicity also makes the root unique.

Facts & Assumptions

Given: AC, the update and filtration in the Statement, a root x∗, the strong-monotonicity inequality, square-integrable x0, and the stated conditional oracle bounds.

[A1]

The Axiom of Choice: AC is assumed for the conditional-expectation and Doob interfaces.

[F1]

Filtration-adapted stochastic-gradient oracles and Robbins–Monro updates: xk+1=xk−αkGk, xk is Fk-measurable, Gk is Fk+1-measurable, vector conditional expectations are coordinatewise almost-sure classes, and E[∥Gk∥22∣Fk]=∥E[Gk∣Fk]∥22+Var⁡(Gk∣Fk) with nonnegative conditional variance.

[F2]

Robbins–Siegmund almost-supermartingale convergence: if Vk is nonnegative adapted integrable and E[Vk+1∣Fk]≤Vk−bk+ck with bk≥0 predictable and ∑ck<∞, then Vk converges almost surely and ∑bk<∞ almost surely.

[F3]

Taking out what is known: a finite Fk-measurable factor may be taken outside conditional expectation when the input and products are integrable.

[F4]

Basic algebra and order properties of conditional expectation: conditional expectation is linear, preserves order, and preserves ordinary expectation.

[F5]

The Euclidean inner product ⟨x,y⟩=∑k<nxkyk on Rn: ∥u∥22=⟨u,u⟩ and the real inner product is symmetric.

[F7]

The principle of mathematical induction: a property true at the first index and inherited by each successor holds at every natural index.

Proof

1.1F1F4F5F6F7givenalgebrainduction

Write Vk=∥xk−x∗∥22. By [F6] and (μ∥u∥2−∥v∥2/μ)2≥0, 2∣⟨u,v⟩∣≤μ∥u∥22+μ−1∥v∥22. The update therefore gives Vk+1≤(1+μαk)Vk+(αk/μ+αk2)∥Gk∥22. By [F4], the conditional moment bound implies E∥Gk∥22≤M2. Using [F1] and nonnegativity of conditional variance gives E[∥h(xk)∥22]≤M2. Thus [F7] and induction from square-integrable x0 show every Vk is integrable; Cauchy–Schwarz makes the products of xk−x∗ with both Gk and h(xk) integrable.

2.1A1F1F3F4F5givenstep 1.1algebra

Strong monotonicity with y=x∗ gives ⟨h(xk),xk−x∗⟩≥μVk. Expanding the update and using [F3] to take out xk−x∗, then [F4] for the conditional mean and moment, yields E[Vk+1∣Fk]≤Vk−2μαkVk+M2αk2. The products are integrable by step 1.1.

3.1A1F2step 1.1step 2.1given

Step 2.1 supplies the conditional inequality required by [F2]. Apply it with ak=0, bk=2μαkVk, and ck=M2αk2. Step 1.1 gives the required integrability, and the stepsize hypotheses make bk predictable and ck summable. Hence Vk converges almost surely and ∑kαkVk<∞ almost surely.

4.1F2step 3.1givenalgebra∎

If the almost-sure limit of Vk were positive, then eventually Vk would be bounded below by half that limit, contradicting ∑kαkVk<∞ and ∑kαk=∞. Thus Vk→0 and xk→x∗ almost surely. If x′ were another root, the strong-monotonicity inequality at (x∗,x′) would give 0≥μ∥x∗−x′∥22, hence x′=x∗.

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